gpt4 book ai didi

go - golang 中的 ECDH - 椭圆/曲线解码失败

转载 作者:行者123 更新时间:2023-12-03 02:23:32 24 4
gpt4 key购买 nike

不幸的是,go 中没有内置的 Brainpool 支持,因此我尝试在 keybase 的分支的帮助下让 ECDH 工作。

也许我在这里犯了一个新手错误,但通过代码在第一个障碍处就失败了(即 elliptic.Unmarshal 返回 nil)?

package main

import (
"fmt"
"io/ioutil"
"log"
"encoding/pem"
"crypto/ecdsa"
"crypto/rand"
"github.com/keybase/go-crypto/brainpool"
"crypto/elliptic"
"crypto/sha256"
)

func main() {
fmt.Println("Hello")
content, err := ioutil.ReadFile("/tmp/TEST.pem")
if err != nil {
log.Fatal(err)
}
fmt.Printf("File contents: %s", content)

block, _ := pem.Decode(content)
if block == nil || block.Type != "PUBLIC KEY" {
log.Fatal("failed to decode PEM")
}

x,y := elliptic.Unmarshal(brainpool.P512r1(),block.Bytes)
if x == nil {
log.Fatal("failed to unmarshal")
}
pubb := ecdsa.PublicKey {brainpool.P512r1(),x,y}


priva, _ := ecdsa.GenerateKey(brainpool.P512r1(), rand.Reader)
b, _ := pubb.Curve.ScalarMult(pubb.X, pubb.Y, priva.D.Bytes())

shared1 := sha256.Sum256(b.Bytes())

fmt.Printf("\nShared key %x\n", shared1)

更新以显示测试 key :

-----BEGIN PUBLIC KEY-----
MIGbMBQGByqGSM49AgEGCSskAwMCCAEBDQOBggAEM/zOLT7nMN374k902oTRZXnG
97DPzvqi8QQJaKXcq1BSrU/sNeUhOi6Y+hBcr7ZE+WZDYNoQkaMNrdhF+3x1XGx7
BTBFL3U1w2ENmkIPiDa2o0Q/wpSOLo/RFabdK5Q3/yvq0hoSdXlpKozE7UTre5cU
bJcUzjXvs9KDLEq54Fs=
-----END PUBLIC KEY-----

最佳答案

您正在尝试解码原始 ASN.1 消息,而不是公钥部分。您应该首先解码 ASN.1 block ,然后解码 EC 数据。

我的评论是错误的,Go 不支持 Brainpool 功能。因此,我从他们的 X509 包中借用了一些代码,为 Brainpool 包中的 6 条曲线构建了一个自定义解析器。

Playground :https://play.golang.org/p/i-Zd4mTugjU

package main

import (
"crypto/ecdsa"
"crypto/elliptic"
"crypto/rand"
"crypto/sha256"
"crypto/x509/pkix"
"encoding/asn1"
"encoding/pem"
"errors"
"fmt"
"log"
"math/big"

"github.com/keybase/go-crypto/brainpool"
)

const ecKey = `-----BEGIN PUBLIC KEY-----
MIGbMBQGByqGSM49AgEGCSskAwMCCAEBDQOBggAEM/zOLT7nMN374k902oTRZXnG
97DPzvqi8QQJaKXcq1BSrU/sNeUhOi6Y+hBcr7ZE+WZDYNoQkaMNrdhF+3x1XGx7
BTBFL3U1w2ENmkIPiDa2o0Q/wpSOLo/RFabdK5Q3/yvq0hoSdXlpKozE7UTre5cU
bJcUzjXvs9KDLEq54Fs=
-----END PUBLIC KEY-----`

func main() {
block, _ := pem.Decode([]byte(ecKey))
if block == nil || block.Type != "PUBLIC KEY" {
log.Fatal("failed to decode PEM")
}

pub, err := parseBrainpoolPKIXPublicKey(block.Bytes)
if err != nil {
log.Fatalf("failed to parse key: %v", err)
}

pubb := ecdsa.PublicKey{Curve: brainpool.P512r1(), X: pub.X, Y: pub.Y}
priva, _ := ecdsa.GenerateKey(brainpool.P512r1(), rand.Reader)
b, _ := pubb.Curve.ScalarMult(pubb.X, pubb.Y, priva.D.Bytes())

shared1 := sha256.Sum256(b.Bytes())

fmt.Printf("\nShared key %x\n", shared1)
}

type publicKeyInfo struct {
Raw asn1.RawContent
Algorithm pkix.AlgorithmIdentifier
PublicKey asn1.BitString
}

type pkcs1PublicKey struct {
N *big.Int
E int
}

var (
oidNamedCurveBrainpoolP256r1 = asn1.ObjectIdentifier{1, 3, 36, 3, 3, 2, 8, 1, 1, 7}
oidNamedCurveBrainpoolP256t1 = asn1.ObjectIdentifier{1, 3, 36, 3, 3, 2, 8, 1, 1, 8}
oidNamedCurveBrainpoolP384r1 = asn1.ObjectIdentifier{1, 3, 36, 3, 3, 2, 8, 1, 1, 11}
oidNamedCurveBrainpoolP384t1 = asn1.ObjectIdentifier{1, 3, 36, 3, 3, 2, 8, 1, 1, 12}
oidNamedCurveBrainpoolP512r1 = asn1.ObjectIdentifier{1, 3, 36, 3, 3, 2, 8, 1, 1, 13}
oidNamedCurveBrainpoolP512t1 = asn1.ObjectIdentifier{1, 3, 36, 3, 3, 2, 8, 1, 1, 14}
)

func parseBrainpoolPKIXPublicKey(derBytes []byte) (pub *ecdsa.PublicKey, err error) {
var pki publicKeyInfo
if rest, err := asn1.Unmarshal(derBytes, &pki); err != nil {
if _, err := asn1.Unmarshal(derBytes, &pkcs1PublicKey{}); err == nil {
return nil, errors.New("failed to parse public key")
}
return nil, err
} else if len(rest) != 0 {
return nil, errors.New("trailing data after ASN.1 of public-key")
}
if !pki.Algorithm.Algorithm.Equal(asn1.ObjectIdentifier{1, 2, 840, 10045, 2, 1}) {
return nil, errors.New("not an ECDSA public key")
}
return parseBrainpoolPublicKey(&pki)
}

func parseBrainpoolPublicKey(keyData *publicKeyInfo) (*ecdsa.PublicKey, error) {
asn1Data := keyData.PublicKey.RightAlign()
paramsData := keyData.Algorithm.Parameters.FullBytes
namedCurveOID := new(asn1.ObjectIdentifier)
rest, err := asn1.Unmarshal(paramsData, namedCurveOID)
if err != nil {
return nil, errors.New("failed to parse ECDSA parameters as named curve")
}
if len(rest) != 0 {
return nil, errors.New("trailing data after ECDSA parameters")
}
namedCurve := namedCurveFromOID(*namedCurveOID)
if namedCurve == nil {
return nil, errors.New("unsupported elliptic curve")
}
x, y := elliptic.Unmarshal(namedCurve, asn1Data)
if x == nil {
return nil, errors.New("failed to unmarshal elliptic curve point")
}
pub := &ecdsa.PublicKey{
Curve: namedCurve,
X: x,
Y: y,
}
return pub, nil
}

func namedCurveFromOID(oid asn1.ObjectIdentifier) elliptic.Curve {
switch {
case oid.Equal(oidNamedCurveBrainpoolP256r1):
return brainpool.P256r1()
case oid.Equal(oidNamedCurveBrainpoolP256t1):
return brainpool.P256t1()
case oid.Equal(oidNamedCurveBrainpoolP384r1):
return brainpool.P384r1()
case oid.Equal(oidNamedCurveBrainpoolP384t1):
return brainpool.P384t1()
case oid.Equal(oidNamedCurveBrainpoolP512r1):
return brainpool.P512r1()
case oid.Equal(oidNamedCurveBrainpoolP512t1):
return brainpool.P512t1()
}
return nil
}

关于go - golang 中的 ECDH - 椭圆/曲线解码失败,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58307704/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com