python - 播放.wav文件x秒

Question

在尝试进入我的代码中的下一个文件之前，我尝试随机播放.wav文件数毫秒。最好的方法是什么？

我目前有以下代码:

#!/usr/bin/env python


from random import randint
import time
import pyaudio

import wave 

while True:
 # random number to indicate wav file name
 x = randint(1,45)
 print ("Note: %d" % x)

# play wav file
chunk = 1024  
f = wave.open(r"%d.wav" % x,"rb")
p = pyaudio.PyAudio()  
stream = p.open(format = p.get_format_from_width(f.getsampwidth()),  
                channels = f.getnchannels(),  
                rate = f.getframerate(),  
                output = True)  
data = f.readframes(chunk)  

while data != '':  
    stream.write(data)  
    data = f.readframes(chunk)  

stream.stop_stream()  
stream.close()
p.terminate()

Answer 1

尝试一下，不知道它是否是干净的代码，但是可以正常工作。

#!/usr/bin/env python


from random import randint
import time
import pyaudio
import threading
import multiprocessing
import wave  


# play wav file
chunk = 1024

def playAudio(x):
    f = wave.open(r"%d.wav" % x,"rb")
    p = pyaudio.PyAudio() 
    stream = p.open(format = p.get_format_from_width(f.getsampwidth()),  
                    channels = f.getnchannels(),  
                    rate = f.getframerate(),  
                    output = True)  
    data = f.readframes(chunk)  

    while data != '':  
        stream.write(data)  
        data = f.readframes(chunk)  

    stream.stop_stream()  
    stream.close()
    p.terminate()

if __name__ == '__main__':
    while True:
        x = randint(1,45)  
        p = multiprocessing.Process(target=playAudio, args=(x,))
        p.start()
        time.sleep(5)
        p.terminate()
        p.join()