python - 类型错误 : 'encoding' is an invalid keyword argument for this function

Question

我的 python 程序无法打开文本文件。当我使用基本打开文件进行读取时，出现 ascii 错误。有人帮助我添加了一个在空闲状态下运行良好的编码参数，但是当我通过终端运行程序时，我收到此错误消息:“TypeError:'encoding'是此函数的无效关键字参数”我该怎么办读取此文本文件以使用其数据？

try:
    import tkinter as tk
    from tkinter import *
except:
    import Tkinter as tk
    from Tkinter import *

import time
import sys
import os
import random

flashcards = {}


def Flashcards(key, trans, PoS):
    if not key in flashcards:
        flashcards[key] = [[trans], [PoS]]
    else:
        x = []
        for item in flashcards[key][0]:
            x.append(item)
        x.append(trans)
        flashcards[key][0] = x
        x = []
        for item in flashcards[key][1]:
            x.append(item)
        x.append(PoS)
        flashcards[key][1] = x


def ImportGaeilge():
    flashcards = {}
    with open('gaeilge_flashcard_mode.txt','r', encoding='utf8') as file:
        for line in file:
            line1 = line.rstrip().split("=")
            key = line1[0]
            trans = line1[1]
            PoS = line1[2]
            Flashcards(key, trans, PoS)

def Gaeilge():
    numberCorrect = 0
    totalCards = 0
    ImportGaeilge()
    wrongCards = {}
    x = input('Hit "ENTER" to begin. (Type "quit" to quit)')
    while x != quit:
        os.system('cls')
        time.sleep(1.3)
        card = flashcards.popitem()
        if card == "":
## WRONG CARDS
            print ("Deck one complete.")
            Gaeilge()
        print("\n\n")
        print(str(card[0])+":")
        x = input("\t:")
        if x == 'quit':
            break
        else:
            right = False
            for item in card[1]:
                if x == card[1]:
                    right = True
                    print("\nCorrect!")
                    numberCorrect += 1
            if right == False:
                print(card[0])

        totalCards += 1
        print("Correct answers:", str(numberCorrect) +"/"+str(totalCards))


Gaeilge()

gaeilge_flashcard_mode.txt:

I=mé=(pron) (emphatic)
I=mise=(n/a)
you=tú=(pron) (subject)
you=tusa=(emphatic)
y'all=sibh=(plural)
y'all=sibhse=(emphatic)
he=sé=(pron)
he=é=(n/a)
he=seisean=(emphatic)
he=eisean=(n/a)
she=sí=(pron)
she=í=(n/a)
she=sise=(emphatic)
she=ise=(emphatic)
him=é=(pron)
him=eisean=(emphatic)
her=í=(pron)
her=ise=(emphatic)
her=a=(adj)

Answer 1

您尝试运行此程序的终端可能使用 Python 2.x 作为标准。

尝试在终端中专门使用命令“Python3”:

$ Python3 yourfile.py

(经过测试并确认 2.7 会给出该错误，而 Python3 可以很好地处理它。)