javascript - promise 所有返回错误太多请求

Question

这个问题已经有答案了:

Executing promises in array with Promise.all breaks them (1 个回答)

已关闭 5 年前。

我使用 Promise all 发送多个 Promise，但收到此错误

429 - {"error":{"code":"TooManyRequests","message":"Too many requests"}}

我有数据列表，我将数据按 10 组进行分块，然后为每个数据发送通知

 await Promise.all(usersList.map(usersTokens=> {

                    return sendPush(heading, content,usersTokens, platform).catch((e) => {
                        console.error(e)
                        errors.push({ e, android })
                    })
                }))

发送推送功能

import * as rp from 'request-promise'
export const sendPush = (title="",secondTitle,tokens,platform) => {


let message = {
    notification_content : {
        name:title,
        title : secondTitle,
        body : secondTitle,

     },
       notification_target : {
       type : "devices_target",
       devices : tokens
     },
   }

 var headers = {
    "Content-Type": "application/json; charset=utf-8",
    "X-API-Token": 'XXXXXXXXXXXXXXXXXXXXXXXXXXX'
};

var options = {
    uri: `https://api.appcenter.ms/v0.1/apps/XXXXXXXXXX/${platform}/push/notifications`,
    method: "POST",
    headers: headers,
    body: message,
    json: true
}

  return rp(options)

}

Answer 1

I chunk data by group of 10

但是您仍然同时请求所有 block 。因此分块的意义不大。您应该使用循环并在处理下一个 block 之前await每个 block ，而不是使用Promise.all:

 const result = [];

 for(const userTokens of userList) {
   try {
     result.push(await sendPush(heading, content,usersTokens, platform));
   } catch(e) {
     console.error(e)
     errors.push({ e, android })
  }
}

如果这对于 API 来说仍然太快，您可以 delay the loop