java - 如何创建可以抛出任何异常的通用函数？

Question

我有两个类(结构示例):

public class A {
    protected void doCheck(stuff) throw CommonException, A1Exception{
        if(stuff==1){
            throw new A1Exception(stuff);
        }
        throw new CommonException(stuff);
    }
    public void invokeAstuff(stuff) throw CommonException, A1Exception{
        doCheck(stuff);
    }
}
public class B {
    protected void doCheck(stuff) throw CommonException, B1Exception{
        if(stuff==1){
            throw new B1Exception(stuff);
        }
        throw new CommonException(stuff);
    }
    public void invokeBstuff(stuff, otherStuff) throw CommonException, B1Exception{
        doCheck(stuff);
    }
}

“doCheck”方法具有相同的处理逻辑，但每个类都有 1 个不同的异常:A 类的 A1Exception 和 B 类的 B1Exception

我的问题是:我如何编写基本类，它将用通用逻辑实现“doCheck”+接受在某些情况下应该抛出的异常类？A 和 B 应该扩展这个类。

Answer 1

您可以创建一个泛型抽象类，将异常声明为泛型类型，然后创建一个必须在子类中重写的供应商方法。

public abstract class Checkable<X extends Exception> {

    protected abstract X getException(int stuff);

    protected void doCheck(int stuff) throws CommonException, X {
        if (stuff == 1) {
            throw this.getException(stuff);
        }
        throw new CommonException(stuff);
    }

}

子类看起来像:

public class A extends Checkable<A1Exception> {

    @Override
    protected A1Exception getException(int stuff) {
        return new A1Exception(stuff);
    }

    public void invokeStuff(int stuff) {
        doCheck(stuff);
    }

}

Ideone Demo