gpt4 book ai didi

javascript - 套索和 D3.js

转载 作者:行者123 更新时间:2023-12-03 01:21:26 26 4
gpt4 key购买 nike

我以为我和这个 SO 用户 here 有类似的问题,但是在将缩小的套索库替换为实际的套索代码后,我仍然没有得到工作输出。

我的代码或多或少与 lasso 的 git hub 上的示例代码相同(我已经对我的设置进行了所需的更改),所以理论上我应该不会有任何问题,对吧?

我只想让套索本身正常工作,然后再附加我自己的样式并返回任何数据。

<script>

var data = [["Arsenal",-0.0032967741593940836, 0.30399753945657115],["Chelsea", 0.2752159801936051, -0.0389675484210763], ["Liverpool",-0.005096951348655329, 0.026678627680541075], ["Manchester City",-0.004715381791104284, -0.12338379196523988], ["Manchester United",0.06877966010653305, -0.0850615090351779], ["Tottenham",-0.3379518099485709, -0.09933664174939877]];

const colours = d3.scaleOrdinal()
.domain(data)
.range(["#F8B195", "#F67280", "#C06C84", "#6C5B7B", "#355C7D", "#2A363B"]);

var canvasW = 675;
var canvasH = 400;
var w = 365;
var h = 365;
var xPadding = 30;
var yPadding = 20;
var padding = 10;

var xScale = d3.scaleLinear()
.range([xPadding, w - padding])
.domain([-1, 1]);

var yScale = d3.scaleLinear()
.range([h - yPadding, padding])
.domain([-1, 1]);

var svg = d3.select('body')
.append("svg")
.attr('width', canvasW)
.attr('height', canvasH);

var lasso_start = function() {
lasso.items()
.attr("r",7)
.classed("not_possible",true)
.classed("selected",false);
};

var lasso_draw = function() {

lasso.possibleItems()
.classed("not_possible",false)
.classed("possible",true);

lasso.notPossibleItems()
.classed("not_possible",true)
.classed("possible",false);
};

var lasso_end = function() {
lasso.items()
.classed("not_possible",false)
.classed("possible",false);

lasso.selectedItems()
.classed("selected",true)
.attr("r",7);

lasso.notSelectedItems()
.attr("r",3.5);

};

svg.selectAll("circle")
.data(data)
.enter()
.append("circle")
.attr("r", 7)
.attr("cx", function(d) { return xScale(d[1]); })
.attr("cy", function(d) { return yScale(d[2]); })
.attr("fill", function(d) {
var result = null;

if (data.indexOf(d) >= 0) {
result = colours(d);
} else {
result = "white";
}
return result;
});

var legend = svg.selectAll(".legend")
.data(colours.domain())
.enter()
.append("g")
.attr("class", "legend")
.attr("transform", function(d, i) { return "translate(0," + i * 29 + ")"; });

legend.append("rect")
.attr("x", canvasW - 184)
.attr("y", 11)
.attr("width", 18)
.attr("height", 18)
.style("fill", colours);

legend.append("text")
.attr("x", canvasW - 194)
.attr("y", 20)
.attr("dy", ".35em")
.style("text-anchor", "end")
.text(function(d) { return d[0];})


var lasso = d3.lasso()
.closePathDistance(75)
.closePathSelect(true)
.area(svg)
.items("circle")
.on("start",lasso_start)
.on("draw",lasso_draw)
.on("end",lasso_end);

svg.call(lasso);

CSS

<style>
@import url('https://fonts.googleapis.com/css?family=Open+Sans+Condensed:300');
@import url("https://fonts.googleapis.com/css?family=Lato:300");
text {
font-family: "Open Sans Condensed";
}
.axis path {
stroke: black;
}

.tick line {
visibility: hidden;
}

.border {
margin-top: 9px;
margin-left: 29px;
border: .5px solid black;
width: 325px;
height: 335px;
position: absolute;
}

.lasso path {
stroke: rgb(80,80,80);
stroke-width:2px;
}

.lasso .drawn {
fill-opacity:.05 ;
}

.lasso .loop_close {
fill:none;
stroke-dasharray: 4, 4;
}

.lasso .origin {
fill:#3399FF;
fill-opacity:.5;
}

.not_possible {
fill:rgb(200,200,200);
}

.possible {
fill:#EC888C;
}

</style>

最佳答案

我以前从未使用过d3.lasso,但查看了this bl.ock using d3 v4 ,看起来您的代码缺少一些小东西:

  1. 现在使用 targetArea 完成要传递给 d3 lasso 的区域

     var lasso = d3.lasso()
    .targetArea(svg)
  2. 传递给 d3 lasso 的项目必须是 d3 选择,而不是字符串

    var circles = svg.selectAll("circle")...

    var lasso = d3.lasso()
    .items(circles)

当然,在脚本标记中使用实际的缩小套索代码,这是一个片段:

https://bl.ocks.org/shashank2104/f878d660bd9013faa6d48236b5fe9502/67d50a5c7a21c0adfa5ed66ce3dc725f0a45c8c2

此外,我还在选定的圆圈中添加了一些 CSS,以便与其他圆圈进行比较:

.selected {
fill: steelblue;
}

希望这有帮助。

关于javascript - 套索和 D3.js,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51755677/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com