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javascript - 在某些单选按钮选择条件下启用禁用的字段集

转载 作者:行者123 更新时间:2023-12-03 01:16:23 27 4
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这是我想要实现的目标:

Remove disabled attribute from the baz fieldset only after both of these conditions are met:

  1. If one or two is checked.
  2. After any bar radio input is checked.

因此,如果选择了 two,则不要从任何 bar 之后的 baz 字段集中删除 disabled 属性输入已检查。

我知道如何解决上面列出的第一个条件,但不知道如何解决第二个条件。我错过了什么?

const form = document.forms[0]
const foo = form.elements.foo
const bazFieldset = form.querySelector("fieldset:last-of-type")

foo.forEach(foo => {
foo.addEventListener("click", () => {
if (foo.value != "three") {
bazFieldset.disabled = false
} else {
bazFieldset.disabled = true
}
})
})
<form>
<fieldset>
<label><input type=radio name=foo value=one>One</label>
<label><input type=radio name=foo value=two>Two</label>
<label><input type=radio name=foo value=three>Three</label>
</fieldset>

<fieldset>
<label><input type=radio name=bar value=four>Four</label>
<label><input type=radio name=bar value=five>Five</label>
<label><input type=radio name=bar value=six>Six</label>
</fieldset>

<fieldset disabled>
<label><input type=radio name=baz value=seven>Seven</label>
<label><input type=radio name=baz value=eight>Eight</label>
<label><input type=radio name=baz value=nine>Nine</label>
</fieldset>
</form>

最佳答案

我会将一个 change 监听器附加到容器,而不是为每个元素分配一个监听器,并使用一个辅助函数,该函数可以接受选择器字符串作为输入,并输出是否检查与该选择器匹配的元素:

const bazFieldset = document.querySelector("fieldset:last-of-type")
const isChecked = selectorStr => document.querySelector(selectorStr + ':checked');
document.forms[0].addEventListener('change', () => {
const enabled = (
(isChecked('[value="one"]') || isChecked('[value="two"]'))
&& isChecked('[name="bar"]')
);
bazFieldset.disabled = !enabled;
});
<form>
<fieldset>
<label><input type=radio name=foo value=one>One</label>
<label><input type=radio name=foo value=two>Two</label>
<label><input type=radio name=foo value=three>Three</label>
</fieldset>

<fieldset>
<label><input type=radio name=bar value=four>Four</label>
<label><input type=radio name=bar value=five>Five</label>
<label><input type=radio name=bar value=six>Six</label>
</fieldset>

<fieldset disabled>
<label><input type=radio name=baz value=seven>Seven</label>
<label><input type=radio name=baz value=eight>Eight</label>
<label><input type=radio name=baz value=nine>Nine</label>
</fieldset>
</form>

关于javascript - 在某些单选按钮选择条件下启用禁用的字段集,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51997279/

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