java - java.io.FileNotFoundException即使文件路径正确

Question

我使用的代码:

package play;

import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;
import java.net.URL;

public class Play {

    InputStream music;
    public Play() {
    URL url=getClass().getResource("/music/Whitewoods - College Kill Dream.mp3");
    System.out.println(url.toString());
    try {
        FileInputStream fileInputStream=new FileInputStream(new File(url.toString()));
        fileInputStream.close();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
        
    }
    public static void main(String args[]) {
        new Play();
        
    }
    
    
    
}

上面的代码下面的行:

System.out.println(url.toString());

prints :
file:/C:/Users/eclipse-workspace/audioboard/bin/music/Whitewoods%20-%20College%20Kill%20Dream.mp3

如果我直接将其复制并放在chrome的url放置框中。文件打开，但该行:

FileInputStream fileInputStream=new FileInputStream(new File(url.toString()));

给出文件未找到错误。
错误堆栈:

java.io.FileNotFoundException: file:\C:\Users\eclipse-workspace\audioboard\bin\music\Whitewoods%20-%20College%20Kill%20Dream.mp3 (The filename, directory name, or volume label syntax is incorrect)
    at java.base/java.io.FileInputStream.open0(Native Method)
    at java.base/java.io.FileInputStream.open(FileInputStream.java:213)
    at java.base/java.io.FileInputStream.<init>(FileInputStream.java:155)
    at play.Play.<init>(Play.java:17)
    at play.Play.main(Play.java:26)

感谢您的帮助。

Answer 1

您可以使用File构造函数File(URI uri)将URL网址转换为URI，并将其作为File构造函数的参数传递，如下所示:

File file = new File(url.toURI());