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javascript - 如何按照线性流程链接 promise ?

转载 作者:行者123 更新时间:2023-12-03 01:10:47 25 4
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我的流程有问题,我正在使用 promise 来做到这一点

上下文是:用户单击按钮以使用 ionic 地理位置获取您的位置,ir 返回纬度和日志,然后我想解码坐标以获取城市,最后一步将纬度、经度和城市设置为用户。

tryGeolocation() {       
this.geolocation.getCurrentPosition().then((resp) => {
let pos = {
lat: resp.coords.latitude,
lng: resp.coords.longitude
};
this.lat = resp.coords.latitude;
this.long = resp.coords.longitude;
console.log(this.lat+"--"+this.long);
this.decodeCoord(this.lat, this.long);
alert(this.city);
this.uploadLocation();
}).catch((error) => {
console.log('Error getting location', error);
this.loading.dismiss();
});
}



decodeCoord(lat, long) {
console.log("decodeCoord");
var latlng = new google.maps.LatLng(lat, long);
this.geocoder.geocode({'latLng': latlng}, function (results, status) {
if (status == google.maps.GeocoderStatus.OK) {
if (results[1]) {
var indice = 0;
for (var j = 0; j < results.length; j++) {
if (results[j].types[0] == 'locality') {
indice = j;
break;
}
}

let city, region, country;
for (var i = 0; i < results[j].address_components.length; i++) {
if (results[j].address_components[i].types[0] == "locality") {
//this is the object you are looking for City
city = results[j].address_components[i];
}
if (results[j].address_components[i].types[0] == "administrative_area_level_1") {
//this is the object you are looking for State
region = results[j].address_components[i];
}
if (results[j].address_components[i].types[0] == "country") {
//this is the object you are looking for
country = results[j].address_components[i];
}
}
//city data
this.city=city;
} else {
console.log("No results found");
}
} else {
console.log("Geocoder failed due to: " + status);
}
});
}



uploadLocation() {
let position = {
latitude: this.lat,
longitude: this.long,
city: this.city
}
this._us.updateUserIndividual(position).then(data => {
console.log("USER UPDATED");
}).catch((err) => {
this.presentToast("Ups! Ha ocurrido un Error, intentalo otra vez");
})
}

我尝试添加 this.decodeCoord(this.lat, this.long);在 uploadLocation 上,但它也不起作用。

这座城市总是空无一人。

最佳答案

this.city 为空,因为您在单独的 this 上下文中分配它。您在定义 this.geocoder.geocode() 时创建了这个新上下文,并使用 function 关键字创建回调函数。用箭头函数替换它,我想你又好了:

this.geocoder.geocode({'latLng': latlng}, (results, status) => {
// ...
});

但我大错特错了。

this.decodeCoord(this.lat, this.long);
alert(this.city);

那是行不通的。因为我让你改变的回调函数,顾名思义,是一个异步函数。因此,您最好从 decodeCoord 方法返回一个 Promise:

decodeCoord(lat, long) {    
return new Promise((resolve, reject) => {
// ...
this.geocoder.geocode({'latLng': latlng}, (results, status) => {
if (status == google.maps.GeocoderStatus.OK) {
// ...
resolve();
} else {
reject();
}
});
});
}

然后你还没有到达那里,你还需要从你的 updateLocation 方法返回 promise :

return this._us.updateUserIndividual(position).

然后您可以更改 tryGeolocation 方法:

async tryGeolocation() {   
try {
const { coords } = await this.geolocation.getCurrentPosition();
this.lat = coords.latitude;
this.long = coords.longitude;

await this.decodeCoord(coords.latitude, coords.longitude);
alert(this.city);
await this.uploadLocation();
} catch (e) {
console.log('Error getting location', e);
} finally {
this.loading.dismiss();
}
}

你就完成了,得到了一个很好的顺序异步等待结果

关于javascript - 如何按照线性流程链接 promise ?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52218067/

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