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javascript - 关于最接近、提交和 AJAX PUT 请求的问题

转载 作者:行者123 更新时间:2023-12-03 01:06:31 24 4
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我在停止表单提交时遇到问题。这是上下文的 html(顺便说一下,我正在使用 EJS):

<form class="edit-form" id="edit-review-form<%= review._id %>" action="/products/<%= product._id %>/reviews/<%= review._id %>" method="POST">
<div class="form-group">
<input class="form-control" type="text" disabled value="<%= currentUser.username %>">
</div>
<div class="form-group">
<input class="form-control" type="text" name="review[subject]" value="<%= review.subject %>" required>
</div>
<div class="form-group">
<input type="number" name="review[rating]" id="rating" class="rating" value="<%=review.rating %>" required/>
</div>
<div class="form-group">
<textarea class="form-control" name="review[text]" placeholder="<%= review.text %>" form="edit-review-form<%= review._id %>" rows="5" cols="70"><%= review.text %></textarea>
</div>
<div class="form-group">
</div>
<button class="reviewButton btn-edit-submit">Edit</button>

这是我的 AJAX 以及一个脚本,行间有注释解释

$(".edit-form").submit(function (event) { // Why does this not? On the developers console this does selects the form, but doesn't stops it from submitting...
event.preventDefault();
let formData = $(this).serialize();
let formAction = $(this).attr("action");
// console.log(formData);
// console.log(JSON.stringify(formData));
$.ajaxSetup({
headers: {"X-CSRF-Token": $("#_csrf").val()}
});
$.ajax({
context: this, /* setting context for ajax callbacks*/
url: formAction,
data: formData,
type: "PUT",
dataType: "json"
})
.done(function(data) {
if (data) {
console.log("Success! = " + JSON.stringify(data));
}
}).fail(function(data) {
console.log("Something went wrong: " + data.responseText);
});
return false;
});

var editReviews = document.getElementsByClassName('btn-edit-submit');
$('.collapse').on("shown.bs.collapse", function(){
//triggers when div is collapse
console.log("collapsed in"); // Works after collapse is finished
for (var i = 0; i < editReviews.length; i++) {
editReviews[i].addEventListener('click', function(event) { // editReviews works in the dev console and every button is selected
event.preventDefault();
// alert("clicked"); // This alert is working,
// PUT Request form
this.closest("form").submit();
});
}
});

此外,如果我从终端提交表单,它不会提交触发 POST 错误的表单(因为它实际上是一个 put 请求),但 AJAX 会通过,如果我单击按钮,它会提交我并启动错误。有什么想法吗?

编辑:也尝试过:

for (var i = 0; i < editReviews.length; i++) {
editReviews[i].addEventListener('click', function(event) { // editReviews works in the dev console and every button is selected
event.preventDefault();
// alert("clicked"); // This alert is working,
// PUT Request form
this.closest("form").submit();
});
}

但是也没有用。

我觉得我还需要提一下,我使用 .closest 选择器的原因是 View 文件中有多种类似的形式。

编辑:谢谢Basmar,尝试了你的建议:

var submitEditForm = function(form) {
form.submit(function (event) { // Why does this not? On the developers console this does selects the form, but doesn't stops it from submitting...
// console.log(this);
let formData = $(this).serialize();
let formAction = $(this).attr("action");
$.ajaxSetup({
headers: {"X-CSRF-Token": $("#_csrf").val()}
});
$.ajax({
context: this, /* setting context for ajax callbacks*/
url: formAction,
data: formData,
type: "PUT",
dataType: "json"
})
.done(function(data) {
if (data) {
console.log("Success! = " + JSON.stringify(data));
}
}).fail(function(data) {
console.log("Something went wrong: " + data.responseText);
});
});
}

var editReviews = document.getElementsByClassName('btn-edit-submit');
for (var i = 0; i < editReviews.length; i++) {
editReviews[i].addEventListener('click', function(event) { // editReviews works in the dev console and every button is selected
event.preventDefault();
// alert("clicked"); // This alert is working,
// PUT Request form
var form = this.closest("form");
form.addEventListener('submit', function(e) {
e.preventDefault();
submitEditForm(form);
});
});
}

它阻止它提交,但 AJAX 请求也不会通过,我做错了吗?

另外,如果我在没有实际使用 .closest() 的情况下提交表单,它确实通过 POST 路由提交,但问题是它提交了第一个 form.edit-form,因为我对它进行了硬编码。

最佳答案

您不应该在 submitEditForm 中调用 form.submit(),您应该只执行 AJAX 代码。

此外,提交按钮的点击监听器应该只调用 submitEditForm(),而不是为表单添加提交处理程序(在另一个监听器中添加事件监听器几乎总是错误的 - 每个单击时,您将添加另一个监听器,并且只有在第一次单击后提交后,提交处理程序才会起作用)。

var submitEditForm = function(form) {

// console.log(this);
let formData = $(form).serialize();
let formAction = $(form).attr("action");
$.ajaxSetup({
headers: {
"X-CSRF-Token": $("#_csrf").val()
}
});
$.ajax({
context: form,
/* setting context for ajax callbacks*/
url: formAction,
data: formData,
type: "PUT",
dataType: "json"
})
.done(function(data) {
if (data) {
console.log("Success! = " + JSON.stringify(data));
}
}).fail(function(data) {
console.log("Something went wrong: " + data.responseText);
});
};

$(".edit-form").submit(function(event) {
event.preventDefault();
submitEditForm(this);
});

var editReviews = document.getElementsByClassName('btn-edit-submit');
for (var i = 0; i < editReviews.length; i++) {
editReviews[i].addEventListener('click', function(event) { // editReviews works in the dev console and every button is selected
event.preventDefault();
// alert("clicked"); // This alert is working,
// PUT Request form
var form = this.closest("form");
submitEditForm(form);
});
}

关于javascript - 关于最接近、提交和 AJAX PUT 请求的问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52380940/

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