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sql - 消息 203,级别 16,状态 2,不是有效标识符

转载 作者:行者123 更新时间:2023-12-03 01:05:00 26 4
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我收到以下错误:

Msg 203, Level 16, State 2, Procedure getQuestion, Line 18
The name 'select top(1) * from tlb_Question inner join tlb_options on tlb_options.qID=tlb_Question.id and tlb_Question.qNumber=1 and tlb_Question.id not in (0,1)' is not a valid identifier

来自以下存储过程:

ALTER proc getQuestion
@qNo bigint,
@total bigint,
@next nvarchar(max)
as
begin
declare @hisa bigint
set @hisa=@total/3

if(@qNo<=@total/3)
begin
declare @query nvarchar(max)
set @query=('select top(1) * from tlb_Question
inner join tlb_options on tlb_options.qID=tlb_Question.id and tlb_Question.qNumber=1 and tlb_Question.id not in ('+cast(@next as varchar)+')')
print @query
execute @query
end
end

最佳答案

请尝试一下,将执行@query更改为执行(@query):

ALTER proc getQuestion
@qNo bigint,
@total bigint,
@next nvarchar(max)
as

begin
declare @hisa bigint
set @hisa=@total/3

if(@qNo<=@total/3)
begin
declare @query nvarchar(max)
set @query=('select top(1) * from tlb_Question
inner join tlb_options on tlb_options.qID=tlb_Question.id and tlb_Question.qNumber=1 and tlb_Question.id not in ('+cast(@next as varchar)+')')
--print @query
execute (@query)
end
end

关于sql - 消息 203,级别 16,状态 2,不是有效标识符,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13205827/

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