php - 如何在 yii2 中添加哈希密码

Question

使用 Yii 2 basic 而非高级版本。

我有一个 CRUD 管理员身份验证系统。它只在数据库中存储 ID、用户名和密码。当用户登录时，如果用户名和密码正确，他们就会登录。

但是我现在想要确保这些密码的安全，所以我想对它们进行加盐和哈希处理。这是我发现很难做的部分，或者更难做到把东西放在哪里。

第 1 部分:我有一个 AdminController 与我的用户模型 Create.php 页面一起使用。第 2 部分:我有一个 siteController，它与 LoginForm 模型和 login.php 页面一起登录。

我将首先讨论第一部分，因为它显然必须在此处实际生成哈希密码。

管理员 Controller :

public function actionCreate()
{
    $model = new User();

    if ($model->load(Yii::$app->request->post()) && $model->save()) {
        return $this->redirect(['view', 'id' => $model->id]);
    } else {
        return $this->render('create', [
            'model' => $model,
        ]);
    }
}

User.php

    <?php

    namespace app\models;
    use yii\base\NotSupportedException;
    use yii\db\ActiveRecord;
    use yii\web\IdentityInterface;
    use yii\data\ActiveDataProvider;
    /**
     * User model
     *
     * @property integer $id
     * @property string $username
     * @property string $password
     */
class User extends ActiveRecord implements IdentityInterface
{


/**
 * @inheritdoc
 */
public static function tableName()
{
    return 'Users';
}


public function rules(){
        return [
            [['username','password'], 'required']
        ];
}



public static function findAdmins(){
    $query = self::find();

    $dataProvider = new ActiveDataProvider([
        'query' => $query,
    ]);

    return $dataProvider;

}


/**
 * @inheritdoc
 */
public static function findIdentity($id)
{
    return static::findOne(['id' => $id]);
}



/**
 * @inheritdoc
 */
public static function findIdentityByAccessToken($token, $type = null)
{
    throw new NotSupportedException('"findIdentityByAccessToken" is not implemented.');
}

/**
 * Finds user by username
 *
 * @param  string      $username
 * @return static|null
 */
public static function findByUsername($username)
{
    return static::findOne(['username' => $username]);
}

/**
 * @inheritdoc
 */
public function getId()
{
    return $this->id;
}

/**
 * @inheritdoc
 */
public function getAuthKey()
{
    return static::findOne('AuthKey');
}

/**
 * @inheritdoc
 */
public function validateAuthKey($authKey)
{
    return static::findOne(['AuthKey' => $authKey]);
}

/**
 * Validates password
 *
 * @param  string  $password password to validate
 * @return boolean if password provided is valid for current user
 */
public function validatePassword($password)
{
    return $this->password === $password;
}
}

问题??:因此，正如您在这个模型中看到的那样，我只有来自数据库的 ID、用户名和密码，所以我认为我需要为数据库中名为“hashed_pa​​ssword”的字段创建一个字段？

创建.php:

<?php $form = ActiveForm::begin(); ?>

<?= $form->field($model, 'username')->textInput(['maxlength' => 50]) ?>

<?= $form->field($model, 'password')->passwordInput(['maxlength' => 50]) ?>

<div class="form-group">
    <?= Html::submitButton($model->isNewRecord ? 'Create' : 'Update', ['class' => $model->isNewRecord ? 'btn btn-success' : 'btn btn-primary']) ?>
</div>

<?php ActiveForm::end(); ?>

对，这就是第 1 部分，需要生成哈希密码并将其保存到数据库中的实际部分，我该如何实现这一点？

好的，继续第二部分:

站点 Controller :

public function actionLogin()
{
    if (!\Yii::$app->user->isGuest) {
        return $this->goHome();
    }

    $model = new LoginForm();

    if ($model->load(Yii::$app->request->post()) && $model->login()) {
        return $this->goBack();
    } else {
        return $this->render('login', [
            'model' => $model,
        ]);
    }
}

LoginForm.php(模型):

class LoginForm extends Model
{
public $username;
public $password;
public $rememberMe = true;

private $_user = false;


/**
 * @return array the validation rules.
 */
public function rules()
{
    return [
        // username and password are both required
        [['username', 'password'], 'required'],
        // rememberMe must be a boolean value
        ['rememberMe', 'boolean'],
        // password is validated by validatePassword()
        ['password', 'validatePassword'],
    ];
}

/**
 * Validates the password.
 * This method serves as the inline validation for password.
 *
 * @param string $attribute the attribute currently being validated
 * @param array $params the additional name-value pairs given in the rule
 */
public function validatePassword($attribute, $params)
{
    if (!$this->hasErrors()) {
        $user = $this->getUser();

        if (!$user || !$user->validatePassword($this->password)) {
            $this->addError($attribute, 'Incorrect username or password.');
        }
    }
}

/**
 * Logs in a user using the provided username and password.
 * @return boolean whether the user is logged in successfully
 */
public function login()
{
    if ($this->validate()) {
        return Yii::$app->user->login($this->getUser(), $this->rememberMe ? 3600*24*30 : 0);
    } else {
        return false;
    }
}

/**
 * Finds user by [[username]]
 *
 * @return User|null
 */
public function getUser()
{
    if ($this->_user === false) {
        $this->_user = User::findByUsername($this->username);
    }

    return $this->_user;
}
}

登录.php:

<?php $form = ActiveForm::begin(); ?>

<?= $form->field($model, 'username'); ?> 
<?= $form->field($model, 'password')->passwordInput(); ?> 


<div class="form-group">
    <div class="col-lg-offset-1 col-lg-11">
        <?= Html::submitButton('Login', ['class' => 'btn btn-primary', 'name' => 'login-button']) ?>
    </div>
</div>

就是这样，我如何在每个用户创建时集成 hashed_pa​​ssword，然后在登录时验证它？

我一直在阅读文档，但就是无法让它工作 http://www.yiiframework.com/doc-2.0/guide-security-passwords.html

Answer 1

当您创建用户时，您应该生成并保存密码哈希。生成它

\Yii::$app->security->generatePasswordHash($password);

要在登录时检查它，请更改实现 UserIdentity 的用户模型

    /**
     * Validates password
     *
     * @param  string $password password to validate
     * @return boolean if password provided is valid for current user
     */
    public function validatePassword($password)
    {
        return Yii::$app->getSecurity()->validatePassword($password, $this->password_hash);
    }

使用数据库中的字段代替password_hash。