javascript - Joi 验证忽略嵌套键

Question

这是我的 Joi 验证:

let schema = Joi.object().keys({
  personal_info: Joi.object().keys({
    first_name: Joi.string().min(2).max(10).regex(Regex.alphabeta, 'alphabeta').required().error(JoiCustomErrors),
    last_name: Joi.string().min(2).max(10).regex(Regex.alphabeta, 'alphabeta').required().error(JoiCustomErrors),
    phone: Joi.string().min(10).max(10).regex(Regex.num, 'num').required().error(JoiCustomErrors),
    nickname: Joi.string().min(3).max(12).regex(Regex.alphanum, 'alphanum').required().error(JoiCustomErrors),
    birthday: Joi.date().max(`01-01-${new Date().getFullYear()-8}`).required().error(JoiCustomErrors),
    IDNumber: Joi.string().min(9).max(9).regex(Regex.num, 'num').required().error(JoiCustomErrors),
    address: Joi.object().keys({
      city: Joi.string().valid(Cities).required().error(JoiCustomErrors),
      street: Joi.string().min(2).max(15).regex(Regex.alphabeta, 'alphabeta').required().error(JoiCustomErrors),
      house_number: Joi.string().min(1).max(5).regex(Regex.alphanum, 'alphanum').error(JoiCustomErrors)
    })
  }),
  permission_level: Joi.number().min(1).max(9).required().error(JoiCustomErrors)
});
Joi.validate(req.body, schema, { abortEarly: false }, (err) => {
  if (err) return cast.joiError(err);
  return create_employee(result);
});

解释:

personal_info 对象内的所有嵌套键都不会被检查。这意味着 - 如果我将 first_name 放在父级上(而不是在 personal_info 下)，架构验证器就会对其进行检查 - 正如应该的那样。

我做错了什么？

Answer 1

在personal_info模式对象上使用.required()，然后它将按照您的预期工作，

'use strict';
const Joi = require('joi');
let schema = Joi.object().keys({
    personal_info: Joi.object().keys({
        first_name: Joi.string().min(2).max(10).required(),
        last_name: Joi.string().min(2).max(10).required()
    }).required(),
    permission_level: Joi.number().min(1).max(9).required()
});
const req = {
    personal_info: {
        first_name: 'AAAA',
        last_name: 'CCCCCC'
    },
    permission_level: 2
};

Joi.validate(req, schema, (err) => {
    console.log(err);
});