vba - 为什么这个 VBA 生成的 QR 码会卡顿？ (仅限条形码-vba-宏)

Question

上下文

我正在 MS Excel 2010 中使用 barcode-vba-macro-only (在 this SO post 中提到)来生成 QR 码。

(条形码将用于方便使用 Girocode 支付账单，但这在这里并不重要，只是说我需要完全按照下面所示的方式构造输入。) p>

问题

VBA 宏创建了很棒的 QR 代码，但不知何故，当给定某些输入时，输出(在 QR 代码中编码)会“结结巴巴”，即重复部分文本。

例如，当给出以下输入时:

BCD
001
1
SCT
SOLADES1HDB
Recipient First and Last Name
DE86672500200000123456
EUR123.45

它产生以下输出:

奇怪地重复了部分内容:

BCD
001
1
SCT
SOLADES1HDB
Recipient First and Last Name
DE
Recipient First and Last Name
DE86672500200000123456
EUR123.45

(请注意出现两次的DE和收件人名字和姓氏行。)

我想要什么

Excel 中有效的免费/GPL 解决方案，用于生成此类代码；-) ...例如，通过了解发生这种情况的原因并修复 VBA 代码。

我尝试过的内容(更新 1)

1. 我尝试过不同的输入，发现只需在长数字的末尾添加一些额外的“AAA”就可以解决口吃问题......所以我很好奇是什么导致了这种情况。

2. 我在 GitHub 上 fork 了代码，添加了一些代码注释并翻译了一些现有的(捷克语)注释

3. 通过一些调试，我发现该实现搞乱了不同编码的起始位置(它存储在数组eb中):在对“进行编码之后”收件人名字和姓氏”，包括换行符和“DE”作为“字节”，它可能会尝试切换到“十进制”或“字母”编码(每个字符只有 3.33 或 5.5 位，而不是 8 位)...但随后会回退以“Byte”格式进行编码，从而导致起始位置错误。

代码

您可以下载我的测试 XLSM 文件 here ，并访问我的 improved code file on GitHub 。

我认为问题可能出在下面所示的核心函数中，即填充数组 eb() 的部分。

Function qr_gen(ptext As String, poptions As String) As String
  Dim encoded1() As Byte ' byte mode (ASCII) all max 3200 bytes
  Dim encix1%
  Dim ecx_cnt(3) As Integer
  Dim ecx_pos(3) As Integer
  Dim ecx_poc(3) As Integer
  Dim eb(1 To 20, 1 To 4) As Integer 'store how many characters should be in which ECI mode. This is a list of rows, each row corresponding a the next batch of characters with a different ECI mode.
  ' eb(i, 1) - ECI mode (1 = numeric, 2 = alphanumeric, 3 = byte)
  ' eb(i, 2) - last character in previous row
  ' eb(i, 3) - number of characters in THIS row
  ' eb(i, 4) - number of bits for THIS row
  Dim ascimatrix$, mode$, err$
  Dim ecl%, r%, c%, mask%, utf8%, ebcnt%
  Dim i&, j&, k&, m&
  Dim ch%, s%, siz%
  Dim x As Boolean
  Dim qrarr() As Byte ' final matrix
  Dim qrpos As Integer
  Dim qrp(15) As Integer     ' 1:version,2:size,3:ccs,4:ccb,5:totby,6-12:syncs(7),13-15:versinfo(3)
  Dim qrsync1(1 To 8) As Byte
  Dim qrsync2(1 To 5) As Byte

  ascimatrix = ""
  err = ""
  mode = "M"
  i = InStr(poptions, "mode=")
  If i > 0 Then mode = Mid(poptions, i + 5, 1)
' M=0,L=1,H=2,Q=3
  ecl = InStr("MLHQ", mode) - 1
  If ecl < 0 Then mode = "M": ecl = 0
  If ptext = "" Then
    err = "Not data"
    Exit Function
  End If
  For i = 1 To 3
    ecx_pos(i) = 0
    ecx_cnt(i) = 0
    ecx_poc(i) = 0
  Next i
  ebcnt = 1
  utf8 = 0
  For i = 1 To Len(ptext) + 1
    ' Decide how many bytes this character has
    If i > Len(ptext) Then
      k = -5 ' End of text --> skip several code sections
    Else ' need to parse character i of ptext and decide how many bytes it has
      k = AscL(Mid(ptext, i, 1))
      If k >= &H1FFFFF Then ' FFFF - 1FFFFFFF
        m = 4
        k = -1
      ElseIf k >= &H7FF Then ' 7FF-FFFF 3 bytes
        m = 3
        k = -1
      ElseIf k >= 128 Then
        m = 2
        k = -1
      Else ' normal 7bit ASCII character, so it is worth it to check if it belong to the Numeric or Alphanumeric subsets defined in ECI (array qralnum)
        m = 1
        k = InStr(qralnum, Mid(ptext, i, 1)) - 1
      End If
    End If
    ' Depending on k and a lot of other things, increase ebcnt
    If (k < 0) Then ' Treat mult-byte case or exit? (bude byte nebo konec)
      If ecx_cnt(1) >= 9 Or (k = -5 And ecx_cnt(1) = ecx_cnt(3)) Then ' Until now it was possible numeric??? (Az dosud bylo mozno pouzitelne numeric)
        If (ecx_cnt(2) - ecx_cnt(1)) >= 8 Or (ecx_cnt(3) = ecx_cnt(2)) Then ' pred num je i pouzitelny alnum
          If (ecx_cnt(3) > ecx_cnt(2)) Then ' Jeste pred alnum bylo byte
            eb(ebcnt, 1) = 3         ' Typ byte
            eb(ebcnt, 2) = ecx_pos(3) ' Position pozice
            eb(ebcnt, 3) = ecx_cnt(3) - ecx_cnt(2) ' delka
            ebcnt = ebcnt + 1
            ecx_poc(3) = ecx_poc(3) + 1
          End If
          eb(ebcnt, 1) = 2         ' Typ alnum
          eb(ebcnt, 2) = ecx_pos(2)
          eb(ebcnt, 3) = ecx_cnt(2) - ecx_cnt(1) ' delka
          ebcnt = ebcnt + 1
          ecx_poc(2) = ecx_poc(2) + 1
          ecx_cnt(2) = 0
        ElseIf ecx_cnt(3) > ecx_cnt(1) Then ' byly bytes pred numeric
          eb(ebcnt, 1) = 3         ' Typ byte
          eb(ebcnt, 2) = ecx_pos(3) ' Position pozice
          eb(ebcnt, 3) = ecx_cnt(3) - ecx_cnt(1) ' delka
          ebcnt = ebcnt + 1
          ecx_poc(3) = ecx_poc(3) + 1
        End If
      ElseIf (ecx_cnt(2) >= 8) Or (k = -5 And ecx_cnt(2) = ecx_cnt(3)) Then ' Az dosud bylo mozno pouzitelne alnum
        If (ecx_cnt(3) > ecx_cnt(2)) Then ' Jeste pred alnum bylo byte
          eb(ebcnt, 1) = 3         ' Typ byte
          eb(ebcnt, 2) = ecx_pos(3) ' Position pozice
          eb(ebcnt, 3) = ecx_cnt(3) - ecx_cnt(2) ' delka
          ebcnt = ebcnt + 1
          ecx_poc(3) = ecx_poc(3) + 1
        End If
        eb(ebcnt, 1) = 2         ' Typ alnum
        eb(ebcnt, 2) = ecx_pos(2)
        eb(ebcnt, 3) = ecx_cnt(2) ' delka
        ebcnt = ebcnt + 1
        ecx_poc(2) = ecx_poc(2) + 1
        ecx_cnt(3) = 0
        ecx_cnt(2) = 0 ' vse zpracovano
      ElseIf (k = -5 And ecx_cnt(3) > 0) Then ' konec ale mam co ulozit
        eb(ebcnt, 1) = 3         ' Typ byte
        eb(ebcnt, 2) = ecx_pos(3) ' Position pozice
        eb(ebcnt, 3) = ecx_cnt(3) ' delka
        ebcnt = ebcnt + 1
        ecx_poc(3) = ecx_poc(3) + 1
      End If
    End If
    If k = -5 Then Exit For
    If (k >= 0) Then ' We can alphanumeric? (Muzeme alnum)
      If (k >= 10 And ecx_cnt(1) >= 12) Then ' Until now it was perhaps numeric (Az dosud bylo mozno num)
        If (ecx_cnt(2) - ecx_cnt(1)) >= 8 Or (ecx_cnt(3) = ecx_cnt(2)) Then ' There is also an alphanumeric which is worth it(Je tam i alnum ktery stoji za to)
          If (ecx_cnt(3) > ecx_cnt(2)) Then ' Even before it was alnum byte (Jeste pred alnum bylo byte)
            eb(ebcnt, 1) = 3         ' Typ byte
            eb(ebcnt, 2) = ecx_pos(3) ' Position (pozice)
            eb(ebcnt, 3) = ecx_cnt(3) - ecx_cnt(2) ' length (delka)
            ebcnt = ebcnt + 1
            ecx_poc(3) = ecx_poc(3) + 1
          End If
          eb(ebcnt, 1) = 2         ' Typ alnum
          eb(ebcnt, 2) = ecx_pos(2)
          eb(ebcnt, 3) = ecx_cnt(2) - ecx_cnt(1) ' length (delka)
          ebcnt = ebcnt + 1
          ecx_poc(2) = ecx_poc(2) + 1
          ecx_cnt(2) = 0 ' processed everything (vse zpracovano)
        ElseIf (ecx_cnt(3) > ecx_cnt(1)) Then ' Previous Num is byte (Pred Num je byte)
          eb(ebcnt, 1) = 3         ' Typ byte
          eb(ebcnt, 2) = ecx_pos(3) ' Position (pozice)
          eb(ebcnt, 3) = ecx_cnt(3) - ecx_cnt(1) ' length (delka)
          ebcnt = ebcnt + 1
          ecx_poc(3) = ecx_poc(3) + 1
        End If
        eb(ebcnt, 1) = 1         ' Typ numerix
        eb(ebcnt, 2) = ecx_pos(1)
        eb(ebcnt, 3) = ecx_cnt(1) ' length (delka)
        ebcnt = ebcnt + 1
        ecx_poc(1) = ecx_poc(1) + 1
        ecx_cnt(1) = 0
        ecx_cnt(2) = 0
        ecx_cnt(3) = 0 ' processed everything (vse zpracovano)
      End If
      If ecx_cnt(2) = 0 Then ecx_pos(2) = i
      ecx_cnt(2) = ecx_cnt(2) + 1
    Else ' possible alnum (mozno alnum)
      ecx_cnt(2) = 0
    End If
    If k >= 0 And k < 10 Then ' Can be numeric (muze byt numeric)
      If ecx_cnt(1) = 0 Then ecx_pos(1) = i
      ecx_cnt(1) = ecx_cnt(1) + 1
    Else
      ecx_cnt(1) = 0
    End If
    If ecx_cnt(3) = 0 Then ecx_pos(3) = i
    ecx_cnt(3) = ecx_cnt(3) + m
    utf8 = utf8 + m
    If ebcnt >= 16 Then ' We have already taken 3 other blocks of bits (Uz by se mi tri dalsi bloky stejne nevesli)
      ecx_cnt(1) = 0
      ecx_cnt(2) = 0
    End If
    Debug.Print "Character:'" & Mid(ptext, i, 1) & "'(" & k & _
        ") ebn=" & ecx_pos(1) & "." & ecx_cnt(1) & _
         " eba=" & ecx_pos(2) & "." & ecx_cnt(2) & _
         " ebb=" & ecx_pos(3) & "." & ecx_cnt(3)
  Next
  ebcnt = ebcnt - 1 ' ebcnt now has its final value
  Debug.Print ("ebcnt=" & ebcnt)
  c = 0
  For i = 1 To ebcnt
    Select Case eb(i, 1)
      Case 1: eb(i, 4) = Int(eb(i, 3) / 3) * 10 + (eb(i, 3) Mod 3) * 3 + IIf((eb(i, 3) Mod 3) > 0, 1, 0)
      Case 2: eb(i, 4) = Int(eb(i, 3) / 2) * 11 + (eb(i, 3) Mod 2) * 6
      Case 3: eb(i, 4) = eb(i, 3) * 8
    End Select
    c = c + eb(i, 4)
  Next i
  Debug.Print ("c=" & c)
'  UTF-8 is default not need ECI value - zxing cannot recognize
'  Call qr_params(i * 8 + utf8,mode,qrp)
  Call qr_params(c, ecl, qrp, ecx_poc)
  If qrp(1) <= 0 Then
    err = "Too long"
    Exit Function
  End If
  siz = qrp(2)
Debug.Print "ver:" & qrp(1) & mode & " size " & siz & " ecc:" & qrp(3) & "x" & qrp(4) & " d:" & (qrp(5) - qrp(3) * qrp(4))
'MsgBox "ver:" & qrp(1) & mode & " size " & siz & " ecc:" & qrp(3) & "x" & qrp(4) & " d:" & (qrp(5) - qrp(3) * qrp(4))
  ReDim encoded1(qrp(5) + 2)
  ' Table 3 — Number of bits in character count indicator for QR Code 2005:
  ' mode indicator (1=num,2=AlNum,4=Byte,8=kanji,ECI=7)
  '      mode: Byte Alphanum  Numeric  Kanji
  ' ver 1..9 :  8      9       10       8
  '   10..26 : 16     11       12      10
  '   27..40 : 16     13       14      12
' UTF-8 is default not need ECI value - zxing cannot recognize
'  if utf8 > 0 Then
'    k = &H700 + 26 ' UTF-8=26 ; Win1250 = 21; 8859-2 = 4 viz http://strokescribe.com/en/ECI.html
'    bb_putbits(encoded1,encix1,k,12)
'  End If
  encix1 = 0
  For i = 1 To ebcnt
    Select Case eb(i, 1)
      Case 1: c = IIf(qrp(1) < 10, 10, IIf(qrp(1) < 27, 12, 14)): k = 2 ^ c + eb(i, 3) ' encoding mode "Numeric"
      Case 2: c = IIf(qrp(1) < 10, 9, IIf(qrp(1) < 27, 11, 13)): k = 2 * (2 ^ c) + eb(i, 3) ' encoding mode "alphanum
      Case 3: c = IIf(qrp(1) < 10, 8, 16): k = 4 * (2 ^ c) + eb(i, 3) ' encoding mode "Byte"
    End Select
    Call bb_putbits(encoded1, encix1, k, c + 4)
    Debug.Print "ver:" & qrp(1) & mode & " size " & siz & " ecc:" & qrp(3) & "x" & qrp(4) & " d:" & (qrp(5) - qrp(3) * qrp(4))
    j = 0 ' count characters that have been output in THIS row eb(i,...)
    m = eb(i, 2) 'Start (after) last character of input from previous row
    r = 0
    While j < eb(i, 3)
      k = AscL(Mid(ptext, m, 1))
      m = m + 1
      If eb(i, 1) = 1 Then
        ' parse numeric input - output 3 decimal digits into 10 bit
        r = (r * 10) + ((k - &H30) Mod 10)
        If (j Mod 3) = 2 Then
          Call bb_putbits(encoded1, encix1, r, 10)
          r = 0
        End If
        j = j + 1
      ElseIf eb(i, 1) = 2 Then
        ' parse alphanumeric input - output 2 alphanumeric characters into 11 bit
        r = (r * 45) + ((InStr(qralnum, Chr(k)) - 1) Mod 45)
        If (j Mod 2) = 1 Then
          Call bb_putbits(encoded1, encix1, r, 11)
          r = 0
        End If
        j = j + 1
      Else
        ' Okay, byte mode: coding according to Chapter "6.4.2 Extended Channel Interpretation (ECI) mode" of ISOIEC 18004_2006Cor 1_2009.pdf
        If k > &H1FFFFF Then ' FFFF - 1FFFFFFF
          ch = &HF0 + Int(k / &H40000) Mod 8
          Call bb_putbits(encoded1, encix1, ch, 8)
          ch = 128 + Int(k / &H1000) Mod 64
          Call bb_putbits(encoded1, encix1, ch, 8)
          ch = 128 + Int(k / 64) Mod 64
          Call bb_putbits(encoded1, encix1, ch, 8)
          ch = 128 + k Mod 64
          Call bb_putbits(encoded1, encix1, ch, 8)
          j = j + 4
        ElseIf k > &H7FF Then ' 7FF-FFFF 3 bytes
          ch = &HE0 + Int(k / &H1000) Mod 16
          Call bb_putbits(encoded1, encix1, ch, 8)
          ch = 128 + Int(k / 64) Mod 64
          Call bb_putbits(encoded1, encix1, ch, 8)
          ch = 128 + k Mod 64
          Call bb_putbits(encoded1, encix1, ch, 8)
          j = j + 3
        ElseIf k > &H7F Then ' 2 bytes
          ch = &HC0 + Int(k / 64) Mod 32
          Call bb_putbits(encoded1, encix1, ch, 8)
          ch = 128 + k Mod 64
          Call bb_putbits(encoded1, encix1, ch, 8)
          j = j + 2
        Else
          ch = k Mod 256
          Call bb_putbits(encoded1, encix1, ch, 8)
          j = j + 1
        End If
      End If
    Wend
    Select Case eb(i, 1)
      Case 1:
        If (j Mod 3) = 1 Then
          Call bb_putbits(encoded1, encix1, r, 4)
        ElseIf (j Mod 3) = 2 Then
          Call bb_putbits(encoded1, encix1, r, 7)
        End If
      Case 2:
        If (j Mod 2) = 1 Then Call bb_putbits(encoded1, encix1, r, 6)
    End Select
'MsgBox "blk[" & i & "] t:" & eb(i,1) & "from " & eb(i,2) & " to " & eb(i,3) + eb(i,2) & " bits=" & encix1
  Next i
  Call bb_putbits(encoded1, encix1, 0, 4) ' end of chain
  If (encix1 Mod 8) <> 0 Then  ' round to byte
    Call bb_putbits(encoded1, encix1, 0, 8 - (encix1 Mod 8))
  End If
  ' padding
  i = (qrp(5) - qrp(3) * qrp(4)) * 8
  If encix1 > i Then
    err = "Encode length error"
    Exit Function
  End If
  ' padding 0xEC,0x11,0xEC,0x11...
  Do While encix1 < i
    Call bb_putbits(encoded1, encix1, &HEC11, 16)
  Loop
  ' doplnime ECC
  i = qrp(3) * qrp(4) 'ppoly, pmemptr , psize , plen , pblocks
  Call qr_rs(&H11D, encoded1, qrp(5) - i, i, qrp(4))
'Call arr2hexstr(encoded1)
  encix1 = qrp(5)
  ' Pole pro vystup
  ReDim qrarr(0)
  ReDim qrarr(1, qrp(2) * 24& + 24&) ' 24 bytes per row
  qrarr(0, 0) = 0
  ch = 0
  Call bb_putbits(qrsync1, ch, Array(&HFE, &H82, &HBA, &HBA, &HBA, &H82, &HFE, 0), 64)
  Call qr_mask(qrarr, qrsync1, 8, 0, 0) ' sync UL
  Call qr_mask(qrarr, 0, 8, 8, 0)   ' fmtinfo UL under - bity 14..9 SYNC 8
  Call qr_mask(qrarr, qrsync1, 8, 0, siz - 7) ' sync UR ( o bit vlevo )
  Call qr_mask(qrarr, 0, 8, 8, siz - 8)   ' fmtinfo UR - bity 7..0
  Call qr_mask(qrarr, qrsync1, 8, siz - 7, 0) ' sync DL (zasahuje i do quiet zony)
  Call qr_mask(qrarr, 0, 8, siz - 8, 0)   ' blank nad DL
  For i = 0 To 6
    x = qr_bit(qrarr, -1, i, 8, 0) ' svisle fmtinfo UL - bity 0..5 SYNC 6,7
    x = qr_bit(qrarr, -1, i, siz - 8, 0) ' svisly blank pred UR
    x = qr_bit(qrarr, -1, siz - 1 - i, 8, 0) ' svisle fmtinfo DL - bity 14..8
  Next
  x = qr_bit(qrarr, -1, 7, 8, 0) ' svisle fmtinfo UL - bity 0..5 SYNC 6,7
  x = qr_bit(qrarr, -1, 7, siz - 8, 0) ' svisly blank pred UR
  x = qr_bit(qrarr, -1, 8, 8, 0) ' svisle fmtinfo UL - bity 0..5 SYNC 6,7
  x = qr_bit(qrarr, -1, siz - 8, 8, 1) ' black dot DL
  If qrp(13) <> 0 Or qrp(14) <> 0 Then ' versioninfo
  ' UR ver 0 1 2;3 4 5;...;15 16 17
  ' LL ver 0 3 6 9 12 15;1 4 7 10 13 16; 2 5 8 11 14 17
    k = 65536 * qrp(13) + 256& * qrp(14) + 1& * qrp(15)
    c = 0: r = 0
    For i = 0 To 17
      ch = k Mod 2
      x = qr_bit(qrarr, -1, r, siz - 11 + c, ch) ' UR ver
      x = qr_bit(qrarr, -1, siz - 11 + c, r, ch) ' DL ver
      c = c + 1
      If c > 2 Then c = 0: r = r + 1
      k = Int(k / 2&)
    Next
  End If
  c = 1
  For i = 8 To siz - 9 ' sync lines
    x = qr_bit(qrarr, -1, i, 6, c) ' vertical on column 6
    x = qr_bit(qrarr, -1, 6, i, c) ' horizontal on row 6
    c = (c + 1) Mod 2
  Next
  ' other syncs
  ch = 0
  Call bb_putbits(qrsync2, ch, Array(&H1F, &H11, &H15, &H11, &H1F), 40)
  ch = 6
  Do While ch > 0 And qrp(6 + ch) = 0
    ch = ch - 1
  Loop
  If ch > 0 Then
    For c = 0 To ch
      For r = 0 To ch
        ' corners
        If (c <> 0 Or r <> 0) And _
           (c <> ch Or r <> 0) And _
           (c <> 0 Or r <> ch) Then
          Call qr_mask(qrarr, qrsync2, 5, qrp(r + 6) - 2, qrp(c + 6) - 2)
        End If
      Next r
    Next c
  End If
 ' qr_fill(parr as Variant, psiz%, pb as Variant, pblocks%, pdlen%, ptlen%)
 ' vyplni pole parr (psiz x 24 bytes) z pole pb pdlen = pocet dbytes, pblocks = bloku, ptlen celkem
  Call qr_fill(qrarr, siz, encoded1, qrp(4), qrp(5) - qrp(3) * qrp(4), qrp(5))
  mask = 8 ' auto
  i = InStr(poptions, "mask=")
  If i > 0 Then mask = val(Mid(poptions, i + 5, 1))
  If mask < 0 Or mask > 7 Then
    j = -1
    For mask = 0 To 7
      GoSub addmm
      i = qr_xormask(qrarr, siz, mask, False)
'      MsgBox "score mask " & mask & " is " & i
      If i < j Or j = -1 Then j = i: s = mask
    Next mask
    mask = s
'    MsgBox "best is " & mask & " with score " & j
  End If
  GoSub addmm
  i = qr_xormask(qrarr, siz, mask, True)
  ascimatrix = ""
  For r = 0 To siz Step 2
    s = 0
    For c = 0 To siz Step 2
      If (c Mod 8) = 0 Then
        ch = qrarr(1, s + 24 * r)
        If r < siz Then i = qrarr(1, s + 24 * (r + 1)) Else i = 0
        s = s + 1
      End If
      ascimatrix = ascimatrix _
         & Chr(97 + (ch Mod 4) + 4 * (i Mod 4))
      ch = Int(ch / 4)
      i = Int(i / 4)
    Next
    ascimatrix = ascimatrix & vbNewLine
  Next r
  ReDim qrarr(0)
  qr_gen = ascimatrix
  Exit Function
addmm:
  k = ecl * 8 + mask
  ' poly: 101 0011 0111
  Call qr_bch_calc(k, &H537)
'MsgBox "mask :" & hex(k,3) & " " & hex(k xor &H5412,3)
  k = k Xor &H5412 ' micro xor &H4445
  r = 0
  c = siz - 1
  For i = 0 To 14
    ch = k Mod 2
    k = Int(k / 2)
    x = qr_bit(qrarr, -1, r, 8, ch) ' svisle fmtinfo UL - bity 0..5 SYNC 6,7 .... 8..14 dole
    x = qr_bit(qrarr, -1, 8, c, ch) ' vodorovne odzadu 0..7 ............ 8,SYNC,9..14
    c = c - 1
    r = r + 1
    If i = 7 Then c = 7: r = siz - 7
    If i = 5 Then r = r + 1 ' preskoc sync vodorvny
    If i = 8 Then c = c - 1 ' preskoc sync svisly
  Next
  Return
End Function  ' qr_gen

Answer 1

为什么会发生这种情况

通过一些调试，我发现原始实现弄乱了不同编码的起始位置(存储在数组 eb 中):在对“收件人名字和姓氏”进行编码后，包括换行符和“DE”为“Byte”，它可能会尝试切换到“Decimal”或“Alphanum”编码(每个字符只有 3.33 或 5.5 位，而不是 8)...但随后又回到“Byte”格式编码，从而起始位置错误。

解决方案

我现在在代码中添加了一些错误检查，可以手动消除口吃。

您可以在 Github 上找到我改进的代码，特别参见barcody.bas .

关键的补充是这部分:

  i = 1
  While i < (ebcnt - 1)
    If eb(i, 2) + eb(i, 3) <> eb(i + 1, 2) Then
        ' oops, this should not happen. First document it:
        Debug.Print ("eb() rows " & i & " and " & i + 1 & " are overlapping!")
        ' Now Lets see if we can fix it:
        wasfixed = False
        For k = i To 1 Step -1
            If eb(k, 2) = eb(i + 1, 2) Then
                ' okay, the row k to i seem to be contained in i+1 and following. Delete k to i ...
                For j = k To ebcnt - (i - k + 1) ' ... by copying upwards all later rows...
                    eb(j, 1) = eb(j + (i - k + 1), 1)
                    eb(j, 2) = eb(j + (i - k + 1), 2)
                    eb(j, 3) = eb(j + (i - k + 1), 3)
                    eb(j, 4) = eb(j + (i - k + 1), 4)
                Next j
                ebcnt = ebcnt - (i - k + 1) ' and correcting the total rowcount
                wasfixed = True
                Exit For
            End If
        Next k
        If Not (wasfixed) Then
            MsgBox ("The input text analysis failed - entering debug mode...")
            Debug.Assert False
        End If
    End If
    i = i + 1
  Wend