javascript - 使用 ES6 从数组 id 中删除对象列表

Question

我有一个包含 id 的数组和数组中包含的具有相同 id 的对象列表，如何从数组 id 中删除基于对象？

数组:

user_ids: [“id001”, “id004”]

对象列表:

{
    {
        “user_id”: “id001”,
        “city”: “Seattle”
    },
    {
        “user_id”: “id002”,
        “city”: “Los Angeles”
    },
    {
        “user_id”: “id003”,
        “city”: “San Francisco”
    },
    {
        “user_id”: “id004”,
        “city”: “San Diego”
    }
}

所以结果是:

{
    {
        “user_id”: “id002”,
        “city”: “Los Angeles”
    },
    {
        “user_id”: “id003”,
        “city”: “San Francisco”
    }
}

Answer 1

数组方法

Array.prototype.filter()

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter

The filter() method creates a new array with all elements that pass the test implemented by the provided function.

Array.prototype.includes()

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/includes

The includes() method determines whether an array includes a certain element, returning true or false as appropriate.

let user_ids = ["id001", "id004"];
let list = [
    {
        "user_id": "id001",
        "city": "Seattle"
    },
    {
        "user_id": "id002",
        "city": "Los Angeles"
    },
    {
        "user_id": "id003",
        "city": "San Francisco"
    },
    {
        "user_id": "id004",
        "city": "San Diego"
    }
];

console.log(list.filter( o => !(user_ids.includes(o.user_id)) ));