powershell - Powershell在搜索字符串后返回下一个单词

Question

我很抱歉，如果这是重复的，但我徒劳地搜索了。我正在尝试在Powershell中的搜索字符串之后返回(包括)作为继续进行的单词。

$wordtest="one two three four"

如何仅提取 包含在内的 two three？

我已经徒劳地尝试了:

$wordtest.substring($wordtest.IndexOf('two') +1)

和

($wordtest.Split('two')[1])

我使用以下方法来工作 独家 three查询:

(($wordtest -split "two")[1].trim() -split ' ')[0]
 three

谢谢。

Answer 1

您也可以为此使用正则表达式:

$wordtest   = "one two three four"
$searchWord = "two"
if ($wordtest -match "($searchWord\s+\w+)") {
    $matches[0]
}

结果

two three

请注意，如果 $searchWord包含正则表达式的特殊字符，例如 .或 $，则需要先 [Regex]::Escape($searchWord)。

正则表达式中的特殊字符

Char    Description                         Meaning
------- ----------------------------------- ---------------------------------------------------------
\       Backslash                           Used to escape a special character
^       Caret                               Beginning of a string
$       Dollar sign                         End of a string
.       Period or dot                       Matches any single character
|       Vertical bar or pipe symbol         Matches previous OR next character/group
?       Question mark                       Match zero or one of the previous
*       Asterisk or star                    Match zero, one or more of the previous
+       Plus sign                           Match one or more of the previous
( )     Opening and closing parenthesis     Group characters
[ ]     Opening and closing square bracket  Matches a range of characters
{ }     Opening and closing curly brace     Matches a specified number of occurrences of the previous