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javascript - 旋转自定义形状会将其移动到 Angular 落

转载 作者:行者123 更新时间:2023-12-03 00:39:18 26 4
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使用translate(width/2,height/2)旋转自定义形状时;旋转( Angular )),它会移动左下角的形状。我尝试将翻译值设置为负值,它修复了它,但原点位于 0,0 。我用过pop(); push()beginShape(); endShape没有成功。

var points = [];
var r;
var lines = 30;

function setup() {
createCanvas(window.innerWidth, window.windowHeight);
angleMode(DEGREES);
// get the points of the corners of the hexagon
r = Math.min(width, height) * 0.4;
var angle = 60;
for (var i = 1; i < 7; i++) {
var tempX = r * sin((angle * i + 30) % 360) + width / 2;
var tempY = r * cos((angle * i + 30) % 360) + height / 2;
points.push([tempX, tempY]);
}
background(0);
stroke(0, 0, 255);
rectMode(CENTER);
}

function draw() {
background(0);
// draw the lines of ...
push();
translate(width/2, height/2);
rotate(frameCount * 0.75);
beginShape();
for (var i = 0; i < points.length; i++) {
// ... the hexagon perimeter
line(points[i][0], points[i][1], points[(i + 1) % 6][0], points[(i + 1) % 6][1]);
var tempAngle = 240 + i * 60;
var tempX = r * 1.1545 * sin(tempAngle) + points[i][0];
var tempY = r * 1.1545 * cos(tempAngle) + points[i][1];
for (var j = 0; j < lines + 1; j++) {
// ... the lines inside the hexagon
var tempAngle2 = tempAngle = (30 / lines * j) + 210 + i * 60;
var distance = r / cos(30 / lines * j);
var tempX2 = distance * sin(tempAngle2) + points[i][0];
var tempY2 = distance * cos(tempAngle2) + points[i][1];;
line(points[i][0], points[i][1], tempX2, tempY2);
}
endShape();
}
pop();
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/p5.js/0.6.1/p5.js"></script>

最佳答案

我认为问题在于您正在使用 x/y 偏移量定义形状的点。通过从点定义中删除 width/2height/2 ,它可以使您的形状居中。​​

var points = [];
var r;
var lines = 30;

function setup() {
createCanvas(window.innerWidth, window.windowHeight);
angleMode(DEGREES);
// get the points of the corners of the hexagon
r = Math.min(width, height) * 0.4;
var angle = 60;
for (var i = 1; i < 7; i++) {
var tempX = r * sin((angle * i + 30) % 360)
var tempY = r * cos((angle * i + 30) % 360)
points.push([tempX, tempY]);
}
background(0);
stroke(0, 0, 255);
//rectMode(CENTER);
}

function draw() {
background(0);
// draw the lines of ...
push();

translate(width/2, height/2);
rotate(frameCount * 0.75);

beginShape();
for (var i = 0; i < points.length; i++) {
// ... the hexagon perimeter
line(points[i][0], points[i][1], points[(i + 1) % 6][0], points[(i + 1) % 6][1]);
var tempAngle = 240 + i * 60;
var tempX = r * 1.1545 * sin(tempAngle) + points[i][0];
var tempY = r * 1.1545 * cos(tempAngle) + points[i][1];
for (var j = 0; j < lines + 1; j++) {
// ... the lines inside the hexagon
var tempAngle2 = tempAngle = (30 / lines * j) + 210 + i * 60;
var distance = r / cos(30 / lines * j);
var tempX2 = distance * sin(tempAngle2) + points[i][0];
var tempY2 = distance * cos(tempAngle2) + points[i][1];;
line(points[i][0], points[i][1], tempX2, tempY2);
}
endShape();
}
pop();
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/p5.js/0.6.1/p5.js"></script>

关于javascript - 旋转自定义形状会将其移动到 Angular 落,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53528593/

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