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google-maps - “未捕获的无效值错误”(: setCenter: not a LatLng or LatLngLiteral object)

转载 作者:行者123 更新时间:2023-12-03 00:39:07 27 4
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我开始了解 PHP 和 JavaScript,将它们混合在 HTML 中并使用 Google Maps API(版本 3)。

我想出了如何“放置”各种标记,但控制台会抛出错误:

" Uncaught InvalidValueError: setCenter: not a LatLng or LatLngLiteral object ".

我认为这是因为循环中创建的 var 并不完全是所需的对象,而是一个字符串,虽然这让我很困惑,但我不知道我是否正确。

这是我的代码:(顺便说一句,我循环的数组是一个数组加一个数组加一个数组,这是其中的一些。它遵循模式,总共有 6 个“地方”):

$locations = array(
array(
'Location' => array(
'Title'=>'Place',
'Description'=>'Some Place',
'Image'=>'pin1.png',
'Latitude'=>'20.681775',
'Longitude'=>'-103.351479'
)
),…

(继续……)。

<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="initial-scale=1.0, user-scalable=no" />
<style type="text/css">
html { height: 100% }
body { height: 100%; margin: 0; padding: 0 }
#map-canvas { height: 100% }
</style>

<script type="text/javascript"
src="https://maps.googleapis.com/maps/api/js?AIzaSyBVfO8LckdOHAot1a8rZW0bmJIoWO2A3os=API_KEY&sensor=true">
</script>


<script type="text/javascript">
function initialize() {
var mapOptions = {
center: (20.68177501, -103.3514794),
zoom: 15,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
var map = new google.maps.Map(document.getElementById("map-canvas"),
mapOptions);

// To add the marker to the map, use the 'map' property
<?php $i = 0; ?>
<?php foreach($locations as $key => $value): ?>
<?php foreach($value as $key => $value): ?>
<?php foreach($value as $key => $value): ?>
<?php if($key == "Latitude"): ?>
<?php $myLatLng = "$value, "; endif;?>
<?php if($key == "Longitude"): ?>
<?php $myLatLng .="$value"; ?>

var myLatlng<?php echo $i; ?> = new google.maps.LatLng(<?php echo $myLatLng; ?>);
var marker<?php echo $i; ?> = new google.maps.Marker({
position: (myLatlng<?php echo $i; ?>),
title:"Hello World!"
});
marker<?php echo $i; ?>.setMap(map);

<?php $i++; ?>
<?php endif; ?>
<?php endforeach; ?>
<?php endforeach; ?>
<?php endforeach; ?>
}
google.maps.event.addDomListener(window, 'load', initialize);
</script>


</head>
<body>
<div id="map-canvas"/>
</body>
</html>

这是 var 分配部分的屏幕截图:

enter image description here

最佳答案

您正在以错误的方式初始化mapOptions

按照以下方式初始化它..

var mapOptions = {
center: new google.maps.LatLng(20.68177501, -103.3514794),
zoom: 15,
mapTypeId: google.maps.MapTypeId.ROADMAP
};

而不是...

var mapOptions = {
center: (20.68177501, -103.3514794), //this is not correct
zoom: 15,
mapTypeId: google.maps.MapTypeId.ROADMAP
};

以下是更正后的代码...

<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="initial-scale=1.0, user-scalable=no" />
<style type="text/css">
html { height: 100% }
body { height: 100%; margin: 0; padding: 0 }
#map-canvas { height: 100% }
</style>

<script type="text/javascript"
src="https://maps.googleapis.com/maps/api/js?AIzaSyBVfO8LckdOHAot1a8rZW0bmJIoWO2A3os=API_KEY&sensor=true">
</script>


<script type="text/javascript">
function initialize() {
var mapOptions = {
center: new google.maps.LatLng(20.68177501, -103.3514794),
zoom: 15,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
var map = new google.maps.Map(document.getElementById("map-canvas"),
mapOptions);

// To add the marker to the map, use the 'map' property
<?php $i = 0; ?>
<?php foreach($locations as $key => $value): ?>
<?php foreach($value as $key => $value): ?>
<?php foreach($value as $key => $value): ?>
<?php if($key == "Latitude"): ?>
<?php $myLatLng = "$value, "; endif;?>
<?php if($key == "Longitude"): ?>
<?php $myLatLng .="$value"; ?>

var myLatlng<?php echo $i; ?> = new google.maps.LatLng(<?php echo $myLatLng; ?>);
var marker<?php echo $i; ?> = new google.maps.Marker({
position: (myLatlng<?php echo $i; ?>),
title:"Hello World!"
});
marker<?php echo $i; ?>.setMap(map);

<?php $i++; ?>
<?php endif; ?>
<?php endforeach; ?>
<?php endforeach; ?>
<?php endforeach; ?>
}
google.maps.event.addDomListener(window, 'load', initialize);
</script>


</head>
<body>
<div id="map-canvas"/>
</body>
</html>

关于google-maps - “未捕获的无效值错误”(: setCenter: not a LatLng or LatLngLiteral object),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19995298/

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