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clojure(带超时...宏)

转载 作者:行者123 更新时间:2023-12-03 00:35:17 25 4
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我正在寻找一个宏,如果表达式完成时间超过 X 秒,它将引发异常。

最佳答案

这个问题在这里有更好的答案: Executing a function with a timeout

future 来救援!

user=> (let [f (future (reduce * (range 1 1001)))]
(.get f 1 java.util.concurrent.TimeUnit/MILLISECONDS))
java.util.concurrent.TimeoutException (NO_SOURCE_FILE:0)

并制作一个宏:

(defmacro time-limited [ms & body]
`(let [f# (future ~@body)]
(.get f# ~ms java.util.concurrent.TimeUnit/MILLISECONDS)))

所以你可以这样做:

user=> (time-limited 1 (reduce * (range 1 1001)))
java.util.concurrent.TimeoutException (NO_SOURCE_FILE:0)
user=> (time-limited 1 (reduce * (range 1 101)))
93326215443944152681699238856266700490715968264381621468592963895217599993229915
608941463976156518286253697920827223758251185210916864000000000000000000000000

关于clojure(带超时...宏),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1683680/

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