javascript - 通过Javascript获取客户端本地IP地址

Question

我们的情况是通过 ASP.Net 应用程序检索客户端本地 IP(不是全局 IP)。

我们发现不可能通过服务器获取此信息，因此我们尝试通过以下方式实现此目的

$(document).ready(function () {
    $.get('http://jsonip.com', function (res) {
        $('p').html('IP Address is: ' + res.ip);
    });
});

但是我们正在获取全局 IP，我们需要本地 IP 地址，任何人都可以帮助我们提供解决方案，提前致谢。

Answer 1

在 HTML5 中，事实证明，最近 HTML5 的 WebRTC 扩展允许 javascript 查询本地客户端 IP 地址。下面的代码片段提供了概念证明

// NOTE: window.RTCPeerConnection is "not a constructor" in FF22/23
var RTCPeerConnection = /*window.RTCPeerConnection ||*/ window.webkitRTCPeerConnection || window.mozRTCPeerConnection;

if (RTCPeerConnection) (function () {
    var rtc = new RTCPeerConnection({iceServers:[]});
    if (1 || window.mozRTCPeerConnection) {      // FF [and now Chrome!] needs a channel/stream to proceed
        rtc.createDataChannel('', {reliable:false});
    };
    
    rtc.onicecandidate = function (evt) {
        // convert the candidate to SDP so we can run it through our general parser
        // see https://twitter.com/lancestout/status/525796175425720320 for details
        if (evt.candidate) grepSDP("a="+evt.candidate.candidate);
    };
    rtc.createOffer(function (offerDesc) {
        grepSDP(offerDesc.sdp);
        rtc.setLocalDescription(offerDesc);
    }, function (e) { console.warn("offer failed", e); });
    
    
    var addrs = Object.create(null);
    addrs["0.0.0.0"] = false;
    function updateDisplay(newAddr) {
        if (newAddr in addrs) return;
        else addrs[newAddr] = true;
        var displayAddrs = Object.keys(addrs).filter(function (k) { return addrs[k]; });
        document.getElementById('list').textContent = displayAddrs.join(" or perhaps ") || "n/a";
    }
    
    function grepSDP(sdp) {
        var hosts = [];
        sdp.split('\r\n').forEach(function (line) { // c.f. http://tools.ietf.org/html/rfc4566#page-39
            if (~line.indexOf("a=candidate")) {     // http://tools.ietf.org/html/rfc4566#section-5.13
                var parts = line.split(' '),        // http://tools.ietf.org/html/rfc5245#section-15.1
                    addr = parts[4],
                    type = parts[7];
                if (type === 'host') updateDisplay(addr);
            } else if (~line.indexOf("c=")) {       // http://tools.ietf.org/html/rfc4566#section-5.7
                var parts = line.split(' '),
                    addr = parts[2];
                updateDisplay(addr);
            }
        });
    }
})(); else {
    document.getElementById('list').innerHTML = "<code>ifconfig | grep inet | grep -v inet6 | cut -d\" \" -f2 | tail -n1</code>";
    document.getElementById('list').nextSibling.textContent = "In Chrome and Firefox your IP should display automatically, by the power of WebRTCskull.";
}

Your network IP is: <h1 id=list>-</h1>