javascript - 使用 JavaScript ES6 迭代器转换数组

Question

这个问题已经有答案了:

Group array items using object (20 个回答)

Most efficient method to groupby on an array of objects (61 个回答)

已关闭 4 年前。

如何使用 javascript es6 迭代器函数将员工数组变量转换为部门数组变量？我正在寻找有效的解决方案。

来自:

var employees = [
    { name: 'John', department: 'Digital Experience' },
    { name: 'Doe', department: 'Digital Transformation' },
    { name: 'Symon', department: 'Digital Planning' },
    { name: 'Joey', department: 'Digital Experience' },
    { name: 'Abul', department: 'Digital Experience' },
    { name: 'Smith', department: 'Digital Experience' },
    { name: 'Ajad', department: 'Digital Transformation' },
    { name: 'Rahim', department: 'Digital Transformation' },
    { name: 'Luke', department: 'Digital Planning' },
];

致:

var departments = [
        {
            department: 'Digital Experience',
            employeeNames: ['Johm', 'Joey', 'Abul', 'Smith']
        },
        {
            department: 'Digital Transformation',
            employeeNames: ['Doe', 'Ajad', 'Rahim']
        },
        {
            department: 'Digital Planning',
            employeeNames: ['Symon', 'Luke']
        }
    ]

Answer 1

我确信还有其他方法，但这看起来相当短。

var e = [
    { name: 'John', department: 'Digital Experience' },
    { name: 'Doe', department: 'Digital Transformation' },
    { name: 'Symon', department: 'Digital Planning' },
    { name: 'Joey', department: 'Digital Experience' },
    { name: 'Abul', department: 'Digital Experience' },
    { name: 'Smith', department: 'Digital Experience' },
    { name: 'Ajad', department: 'Digital Transformation' },
    { name: 'Rahim', department: 'Digital Transformation' },
    { name: 'Luke', department: 'Digital Planning' },
];

const departments = [...new Set(e.map(x => x.department))].map(y => {
  return {
    department: y,
    employeeNames: e.filter(z => z.department === y).map(w => w.name)
  }
})

console.log(departments)