python - 在音频文件中制作与python重叠的 block

Question

我想从我的音频文件中制作 block 以便在 block 之间重叠。例如，如果每个 block 的长度为 4 秒，第一个 block 从 0 到 4 开始，重叠的步长是 1 秒，那么第二个 block 应该从 3 到 7 开始。根据这个 How to splice an audio file (wav format) into 1 sec splices in python? ,我用 pydub用于执行此操作的模块和 make_chunks(your_audio_file_object, chunk_length_ms)方法，但它在 block 之间没有重叠，只是将音频文件切成固定长度的 block 。有人对此有想法吗？谢谢

Answer 1

这是一种方法:

import numpy as np
from scipy.io import wavfile

frequency, signal = wavfile.read(path)

slice_length = 4 # in seconds
overlap = 1 # in seconds
slices = np.arange(0, len(signal)/frequency, slice_length-overlap, dtype=np.int)

for start, end in zip(slices[:-1], slices[1:]):
    start_audio = start * frequency
    end_audio = (end + overlap)* frequency
    audio_slice = signal[int(start_audio): int(end_audio)]

本质上，我们执行以下操作:

加载文件及其对应的频率。为了举例，我假设它的单 channel ，多 channel 它可以工作，只是更多的代码。

定义所需的切片长度和重叠。该数组将为我们提供每个音频片段的开始。通过进一步压缩它并添加重叠，我们得到了所需的 block 。

要说服自己切片有效，请查看以下代码段:

slice_length = 4 # in seconds
overlap = 1 # in seconds
slices = np.arange(0, 26, slice_length-overlap, dtype=np.int) # 26 is arbitrary

frequency = 1
for start, end in zip(slices[:-1], slices[1:]):
    start_audio = start * frequency
    end_audio = (end + overlap) * frequency 
    print(start_audio, end_audio)

输出:

0 4
3 7
6 10
9 13
12 16
15 19
18 22
21 25