blackberry - 如何在Blackberry中连续播放音频文件？

Question

我想创建一个Blackberry应用程序，该应用程序可以连续播放几个音频文件。但是我创建的应用程序可以连续打开所有音频文件，但无法播放整个音频文件。谁能知道解决方案？下面是我的代码:

     package mypackage;

import javax.microedition.media.Manager;
import javax.microedition.media.MediaException;
import javax.microedition.media.Player;
import java.lang.Class;
import javax.microedition.rms.RecordStore;
import java.io.InputStream;
import java.io.ByteArrayInputStream;
import net.rim.device.api.media.protocol.ByteArrayInputStreamDataSource;
import net.rim.device.api.system.*;
import net.rim.device.api.ui.*;
import net.rim.device.api.ui.component.*;
import net.rim.device.api.ui.container.MainScreen;
import net.rim.device.api.ui.extension.container.*;
import net.rim.device.api.ui.UiApplication;
import java.io.IOException;

public class PlayMedia extends UiApplication{
    /**
     * Entry point for application
     * @param args Command line arguments (not used)
     */ 
    public static void main(String[] args){

        PlayMedia theApp = new PlayMedia();
        theApp.enterEventDispatcher();
    }

    public PlayMedia()
    {

        pushScreen(new PlayMediaScreen());


    }
    /**
     * A class extending the MainScreen class, which provides default standard
     * behavior for BlackBerry GUI applications.
     */
    final class PlayMediaScreen extends MainScreen
    {
        /**
         * Creates a new PlayMediaScreen object
         */
        PlayMediaScreen()
        {
            String test1 = "Test(2seconds).mp3";
            String test2 = "Test(2seconds)2.mp3";
            String test3 = "Test(2seconds)3.mp3";
            String test4 = "Test(2seconds)4.mp3";
            String test5 = "blind_willie.mp3";
            String mp3 = null;

            for(int i=0;i<5;i++){
                if(i == 0){
                    mp3 = test1;
                }
                else if(i == 1){
                    mp3 = test2;
                }
                else if(i == 2){
                    mp3 = test3;
                }
                else if(i == 3){
                    mp3 = test4;
                }
                else if(i == 4){
                    mp3 = test5;
                }
                play(mp3);
            }
        }

        private void play(String mp3){

        Player p = null;

        InputStream stream = (InputStream)this.getClass().getResourceAsStream("/" + mp3);

            try {
                //p = Manager.createPlayer(source);
                p = Manager.createPlayer(stream, "audio/mpeg");
                p.realize();
                p.prefetch();

                //testing
                System.out.println("Creating Players!!!!!!!!!!!!!!!!!!!!!!!!!!!!!");
                System.out.println("The mp3 is " + mp3 + "!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!");

            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();

                //testing
                System.out.println("IO Exeception!!!!!!!!!!!!!!!!1 " + e);

                //testing 
                System.out.println(p);

            } catch (MediaException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();

            //testing
            System.out.println("Media Exeception!!!!!!!!!!!!!!!!1" + e);

            //testing 
            System.out.println(p);
            }
            /*
             * Best practice is to invoke realize(), then prefetch(), then start().
             * Following this sequence reduces delays in starting media playback.
             *
             * Invoking start() as shown below will cause start() to invoke  prefetch(0),
             * which invokes realize() before media playback is started.
             */
            try {
                p.start();
            } catch (MediaException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();

                //testing
                System.out.println("Media Exeception for starting!!!!!!!!!!!!!!!!1" + e);

                //testing 
                System.out.println(p);
            }

            try {
                p.stop();
            } catch (MediaException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            p.deallocate();
            p.close();



        }
    }

}

Answer 1

例如，您可以将要播放的文件保存在Vector中，并创建一个队列，该队列将从播放第一个开始，到播放完毕将从第二个开始。
因此，在ur vector 中，您将拥有test1，test2，test3 ...，然后将播放test1。完成后，您将以test2开始...