javascript - 迭代对象数组并将它们放入单独的工厂函数中的最佳方法是什么？

Question

例如，假设我有 data = [{car: "ford", year: "1982"}, {car: "toyota", year: "1999"}] .

  //factory function
  function Car(type, year) {

     return {
        type,
        year,
        identity() {

           return "I am a " + year + " " + type

        }

     }  

  }

  let arr = []
  data.forEach((x) => {

     // would this be the correct way to turn these into factory function 
     // objects?
     arr.push(Car(x.car, x.year))

  })

是否有更好的方法来做到这一点，以便每个 Car() 都有一个与之关联的变量？

Answer 1

var data = [{car: "ford", year: "1982"}, {car: "toyota", year: "1999"}];

function Car(type, year) {

     return {
        type,
        year,
        identity() {

           return "I am a " + year + " " + type

        }

     }  

  }

// Use Map. Map iterates over your array, at each
// element it will call the supplied callback argument
// with the current element. Whatever your function returns
// will be mapped to a new array
// at the same index as the element passed to your callback

const arr = data.map(({ car, year }) => Car(car, year))

console.log(arr);