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node.js - Firebase Flashlight(ElasticSearch)过滤,排序,分页

转载 作者:行者123 更新时间:2023-12-03 00:12:15 25 4
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我正在使用Flashlight Firebase插件

我正在使用这个example并且工作正常

在示例中,您可以看到 example.js 文件具有如下查询方法

  // display search results
function doSearch(index, type, query) {

var ref = database.ref().child(PATH);
var key = ref.child('request').push( { index: index, type: type, query: query } ).key;
ref.child('response/'+key).on('value', showResults);

}

当我传递以下 JSON 之类的值时,上述函数将返回结果
{ index: index, type: type, query: query }

当我尝试传递类似于 的JSON 之类的值时,它什么也没有返回
{ index: index, type: type, query: { "from" : 1, "size" : 5 , "query": query }

但是以下 ElasticSearch API 向我返回了结果
http://localhost:9200/firebase/user/_search?q=*mani*&pretty&size=5&from=1

以及如何使用Flashlight过滤查询,如下所示
{
"query": {
"filtered": {
"query": {
"query_string": {
"query": "drama"
}
},
"filter": {
//Filter to apply to the query
}
}
}
}

我正在使用以下安全规则
{
"rules": {

".read": false,
".write": false,
"search": {
"request": {
"$recid": {
// I can only read records assigned to me
".read": "auth.id === data.child('id').val() || auth.uid === data.child('id').val()",
// I can only write new records that don't exist yet
".write": "!data.exists() && (newData.child('id').val() === auth.id || newData.child('id').val() === auth.uid)",
".validate": "newData.hasChildren(['query', 'index', 'type'])",
"index": {
// accepts arrays or strings
".validate": "(newData.isString() && newData.val().length < 1000) || newData.hasChildren()",
"$child": {
".validate": "newData.isString() && newData.val().length < 1000"
}
},
"type": {
// accepts arrays or strings
".validate": "(newData.isString() && newData.val().length < 1000) || newData.hasChildren()",
"$child": {
".validate": "newData.isString() && newData.val().length < 1000"
}
},
"query": {
// structure of the query object is pretty open-ended
".validate": "newData.isString() || newData.hasChildren()"
},
"$other": {
".validate": false
}
}
},
"response": {
"$recid": {
// I can only read/write records assigned to me
".read": "auth.id === data.child('id').val() || auth.uid === data.child('id').val()",
".write": "auth.id === data.child('id').val() || auth.uid === data.child('id').val()",
// Assumes that Flashlight will be writing the records using a secret or a token that has admin: true
// The only thing a logged in user needs to do is delete results after reading them
".validate": false
}
}
}
}
}

请让我知道如何使用Flashlight执行复杂的查询和过滤

最佳答案

最后我自己做了

这是解决方案

您需要更新SearchQueue.js

_process: function (snap) {
var dat = snap.val();
var key = snap.key;

if (this._assertValidSearch(key, dat)) {

// get your query string

var q = dat.query.query;
console.log('search', "test", JSON.stringify(dat, null, 2));
// build your ES query
//var q1 = {"query":{"match":{"_all":q}}};
// Perform (a very simple) ElasticSearch query
this.esc.search({
index: dat.index,
type: dat.type,
// add options
from : dat.query.from,
size : dat.query.size,
// add ES Query
//body : q1
q:dat.query.query
}, function (error, response) {
if (error) {
this._reply(key, {error: error, total: 0});
} else {
this._reply(key, response);
}
}.bind(this));
}
}

并更新 Example.js
   // display search results
function doSearch(index, type, query) {
var ref = database.ref().child(PATH);
var jsonOBJ = {
index: index,
type: type,
query: { size:1, from:0, query:query},
};
var key = ref.child('request').push(jsonOBJ).key;
console.log('search', key, JSON.stringify(jsonOBJ, null, 2));
ref.child('response/'+key).on('value', showResults);
}

关于node.js - Firebase Flashlight(ElasticSearch)过滤,排序,分页,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39714693/

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