python - Pyglet，播放器，下一首歌

Question

我正在尝试通过pyglet在Python 3中播放歌曲。我可以播放和停止播放一首歌曲，但是当我尝试播放下一首歌曲时会产生错误。 I followed these instructions.我将在tkinter中执行该程序。

我的代码:

import pyglet
import glob
from tkinter import Tk, Button
songs=glob.glob("*.mp3")
player=pyglet.media.Player()
def play_song():
    global player
    for i in range(len(songs)):
        source=pyglet.resource.media(songs[i])
        player.queue(source)
    player.play()
def pause_song():
    player.pause()
def next_song():
    player.next()

window=Tk()
play_=Button(text="play", command=play_song)
play_.pack()
pause_=Button(text="pause", command=pause_song)
pause_.pack()
next_=Button(text="next", command=next_song)
next_.pack()
window.mainloop()

错误:

Exception in Tkinter callback
Traceback (most recent call last):
   File "C:\Python33\lib\tkinter\__init__.py", line 1442, in __call__
   return self.func(*args)
  File "C:\Documents and Settings\Fany\Dokumenty\Hudba\Sabaton\2012 - Carolus Rex\py.py", line 15, in next_song
    player.next()
 AttributeError: 'Player' object has no attribute 'next'

Answer 1

尝试对您的next_song()进行以下更改

def next_song():
    player.next_source()

原因
引用此页
https://pyglet.readthedocs.org/en/pyglet-1.2-maintenance/api/pyglet/media/pyglet.media.Player.html#pyglet.media.Player.time

您会发现next()已“弃用”，建议使用next_source()而不是

高温超导

PS 当我在您的计算机上测试了您的代码片段时，它可以正常工作。