javascript - TypeScript 映射类型推断未按预期工作

Question

鉴于此功能:

export const combineValidators = <Input extends { [P in keyof Input]: (val: string) => Err }, Err>(
  validators: Input
) => (values: { [P in keyof Input]?: unknown }): { [P in keyof Input]: Err } => {
  // Ignore implementation.
  return {} as { [P in keyof Input]: Err };
};

这个用法:

const validator = combineValidators({
  name: (val) => val ? undefined : 'error',
  email: (val) => val ? undefined : 'error'
});

const errors = validator({
  name: 'Lewis',
  email: 'lewis@mercedes.com'
});

我希望 TypeScript 能够将返回类型推断为:

// Expected: `errors` to be inferred as:
interface Ret {
  name: string | undefined;
  email: string | undefined;
}

但是推断为:

// Actual: `errors` inferred as:
interface Ret {
  name: {};
  email: {};
}

我创建了一个 live example in the TypeScript playground演示该问题。

有人可以帮忙吗？

Answer 1

Err 不会按照您期望的方式推断。使用 ReturnType 条件类型从 Input 中提取返回类型可能会更简单:

type ReturnTypes<T extends Record<keyof T, (...a: any[]) => any>> = {
  [P in keyof T]: ReturnType<T[P]>
}

export const combineValidators = <Input extends Record<keyof Input, (val: unknown) => any>>(
  validators: Input
) => (values: Record<keyof Input, unknown>): ReturnTypes<Input> => {
  return {} as ReturnTypes<Input>;
};

const validator = combineValidators({
  name: (val) => val ? undefined : 'error',
  email: (val) => val ? undefined : 'error'
});

const errors = validator({
  name: 'Lewis',
  email: 'lewis@mercedes.com'
});

我们甚至可以更进一步，如果您在验证器函数中指定参数类型，则可以对传递给验证器的对象字段进行类型检查:

type ParamTypes<T extends Record<keyof T, (a: any) => any>> = {
  [P in keyof T]: Parameters<T[P]>[0]
}

type ReturnTypes<T extends Record<keyof T, (...a: any[]) => any>> = {
  [P in keyof T]: ReturnType<T[P]>
}

export const combineValidators = <Input extends Record<keyof Input, (val: unknown) => any>>(
  validators: Input
) => (values: ParamTypes<Input>): ReturnTypes<Input> => {
  return {} as ReturnTypes<Input>;
};

const validator = combineValidators({
  name: (val: string) => val ? undefined : 'error',
  email: (val) => val ? undefined : 'error', // if we leave it out, we still get unknown
  age: (val: number) => val ? undefined : 'error'
});

const errors = validator({
  name: 'Lewis',
  email: 'lewis@mercedes.com',
  age: 0
});

const errors2 = validator({
  name: 'Lewis',
  email: 'lewis@mercedes.com',
  age: "0" // type error
});