javascript - Screeps-如何使路径计算一致？

Question

我有一个用于创建房间布局的原型(prototype)。我正在尝试计算放置容器的位置:

the closest point between the spawn and the controller that is one unit away from the controller

出于某种原因，它似乎给了我多个值(可能是由于路径算法)，即跳转点 according to the API 。我怎样才能每次得到相同的结果，而不是三个不同的点？

Room.prototype.layoutRoom=function(){
    var s:Spawn=this.spawns()[0]
    var c:Controller=this.controller;

    //get path from spawn to controller
    var path = this.findPath(s.pos, c.pos, {ignoreDestructibleStructures: true});

    //place container on last part of path -3 to stay 1 away from controller, and closest to spawn
    //length-1= on endpoint, -2 is one step away, -3 is two steps away 
    var loc=path[path.length-3]
    console.log('layout room, put container: '+loc.x+' '+loc.y)
    this.createConstructionSite(loc.x, loc.y, STRUCTURE_CONTAINER);
}

多次运行上面的代码(这是必需的)会产生多个构建站点:

Answer 1

默认情况下，路径查找会将小兵视为不可通行的方 block 。要解决此问题，请将其添加到选项中:

ignoreCreeps: true