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javascript - 我必须点击搜索按钮两次才能从 api 获取数据

转载 作者:行者123 更新时间:2023-12-02 23:47:54 27 4
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当我第一次单击搜索按钮时,出现两个错误:

  1. main.js:68 GET https://cors-anywhere.herokuapp.com/https://api.darksky.net/forecast/API_key/ 404 (Not Found)

  2. Uncaught (in promise) SyntaxError: Unexpected token N in JSON at position 0.

但是当我第二次单击搜索按钮时,错误消失了。所以我必须点击搜索按钮两次才能从 API 获取数据。

index.html

<form class="searchForm" method="POST">
<div class="form-div">
<label for="loaction">Enter a location</label>
<input type="text" class="searchForm-input" id="loaction" placeholder="Location">
<button type="submit">Search</button>
</div>
</form>
<div class="echo">--</div>
<div class="location">
<h1 class="location-timezone">Timezone</h1>
</div>
<div class="temperature">
<div class="degree-section">
<h2 class="temperature-degree">34</h2>

<span>F</span>

</div>
</div>

main.js

let lat1 = '';
let form = document.querySelector('.searchForm');
form.addEventListener('submit', handleSubmit);

function handleSubmit(event) {
event.preventDefault();
const input = document.querySelector('.searchForm-input').value;
// remove whitespace from the input
const searchQuery = input.split(' ').join('+');
// print `searchQuery` to the console
console.log(searchQuery);

let geocodeURL = `https://maps.googleapis.com/maps/api/geocode/json?
address=${searchQuery}&key=api_key`;

fetch(geocodeURL)
.then(response => {
return response.json();
})
.then(data => {

let max = data.results[0].geometry.location;
console.log(max);

let max1 = max.lat + ',' + max.lng;
console.log(max1);
lat1 = max1;
console.log(lat1);
})
console.log(geocodeURL);


let temperatureDegree = document.querySelector('.temperature-degree');
let locationTimezone = document.querySelector('.location-timezone');
let echos = document.querySelector('.echo');
echos.textContent = searchQuery;

const proxy = 'https://cors-anywhere.herokuapp.com/';
const api =
`${proxy}https://api.darksky.net/forecast/aki_key/${lat1}`;

fetch(api)
.then(response => {
return response.json();
})
.then(data => {
console.log(data);
const {temperature} = data.currently;
temperatureDegree.textContent = temperature;

locationTimezone.textContent = data.timezone;

})
}

最佳答案

您有两个异步操作,其中第二个操作需要使用第一个 AJAX 操作的结果才能继续:

fetch(geocodeURL)
.then(response => {
return response.json();
})
.then(data => {

let max = data.results[0].geometry.location;
console.log(max);

let max1 = max.lat+',' + max.lng;
console.log(max1);
lat1 = max1; <-- lat1 is used in second AJAX call
console.log(lat1);
})
console.log(geocodeURL);

稍后几行:

        const proxy = 'https://cors-anywhere.herokuapp.com/';
const api =
`${proxy}https://api.darksky.net/forecast/aki_key/${lat1}`; // <-- lat1 will be undefined

因此,当您单击搜索按钮时,第一个按钮将触发,当它返回时,它将填充 lat1多变的。由于这是 Promise 的结果,一旦实现它就会触发,同时主线程将继续并执行下一个 fetch(api)声明无需等待 lat1要设置。只需将第二个 AJAX 调用移至 Promise 解析即可:

event.preventDefault();
const input = document.querySelector('.searchForm-input').value;
// remove whitespace from the input
const searchQuery = input.split(' ').join('+');
// print `searchQuery` to the console
console.log(searchQuery);

let geocodeURL = `https://maps.googleapis.com/maps/api/geocode/json?
address=${searchQuery}&key=api_key`;

fetch(geocodeURL)
.then(response => {
return response.json();
})
.then(data => {

let max = data.results[0].geometry.location;
console.log(max);

let max1 = max.lat+',' + max.lng;
console.log(max1);
lat1 = max1;
console.log(lat1);

let temperatureDegree = document.querySelector('.temperature-
degree');
let locationTimezone = document.querySelector('.location-timezone');
let echos = document.querySelector('.echo');
echos.textContent = searchQuery;

const proxy = 'https://cors-anywhere.herokuapp.com/';
const api =
`${proxy}https://api.darksky.net/forecast/aki_key/${lat1}`;

fetch(api)
.then(response => {
return response.json();
})
.then(data => {
console.log(data);
const {temperature} = data.currently;
temperatureDegree.textContent = temperature;

locationTimezone.textContent = data.timezone;

})
}
})
console.log(geocodeURL);

关于javascript - 我必须点击搜索按钮两次才能从 api 获取数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55773901/

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