javascript - ES6 类默认值与数组

Question

一切正常，直到第二次发生接触。

TypeError: Cannot set property 'name' of undefined

因为构造函数中的默认联系人只出现了 1 次。有什么办法可以解决这个问题吗？

class Cust {
  constructor(custData) {

    this.address = {
      countryCode: null,
      address1: null,
      address2: null,
      city: null,
      countrySubDivision: null,
      postalCode: null
    },
    this.groupId = null;
    this.contact = [{ name: null, phone: null }];  
    //this.contact.phone = custData.contact.phone    
    this.state = this._getState(custData.status || null);

    this._setData(custData);
  }

  _getState(status) {
    let state = (status == 'active' ? 'good' : 'bad');
    return state;
  }
  _setData(data, prefix, index) {
    let result;
    for (let key in data) {
      let value = data[key];
      let valueIsNullOrEmpty = !value;
      if (!valueIsNullOrEmpty && typeof value === 'object') {
        if (Array.isArray(value)) {
          value = value
            .map((subProperty, index) => this._setData(subProperty, key, index))
            .filter((subProperty) => Object.keys(subProperty).length > 0);
          valueIsNullOrEmpty = value.length === 0;
          continue;
        } else {
          value = this._setData(value, key);
          valueIsNullOrEmpty = Object.keys(value).length === 0;
          continue;
        }
      }
      if (prefix) {
        if (index >= 0) {
          this[prefix][index][key] = data[key];
        }
        else {
          this[prefix][key] = data[key];
        }
      }
      else {
        this[key] = data[key]
      }
      result = data[key];

    }
    console.log(JSON.stringify(this));
    return result;
  }
}

var custData = {
  id: 1,
  name: "Barr",
  //  groupId: 2,
  status: "active",
  address: {
    countryCode: "USA",
    address1: "123 main street",
    address2: null,
    city: "Chicago",
    postalCode: "85001"
  }, contact: [
    {
      phone: "222-222-2222"
    },
    {
      name: "Tim"
    }]
}
var cust = new Cust(custData);

Answer 1

您正在递归地格式化数据，但您总是尝试从 this 更改变异数据，例如

  this[key]

这适用于深度 1，但对于深度为 5 的情况，它会变得复杂:

 this[key1][key2][key3][key4][key5]

您明白了(这就是您的代码实际上失败的地方，访问深度大于 2 的嵌套对象的属性)。

这个永远不会起作用。相反，您可以通过传递对象来修改方法(可以是一个函数)，然后通过返回一个新对象(这将使调试更容易)来保持它不可变:

 function format(obj) {
    const result = {};
   //...
   return result;
 }

然后您可以轻松地使用嵌套对象调用format。从类内部可以调用为:

  Object.assign(this, format(data));