javascript - 如何在javascript中通过属性删除对象

Question

我想知道如何通过嵌套数组对象中的属性删除对象

我在sampleobj中有完整的对象列表，将每个id与apitrans，apifund进行比较，如果成功为假，则删除sampleobj中的obj

如果成功为 false，则删除 Sampleobj 中的对象。

我已经尝试过:

var result = sampleobj.foreach(e=>{
   if(e.id === "trans" && apitrans.success== true){
      Object.assign(e, apitrans);
   }
  if(e.id === "fund" && apifund.success== true){
      Object.assign(e, apifund);
   }

  // if success false remove the object.
})

//inputs scenario 1
var sampleobj=[{
    id: "trans",
    amount: "100",
    fee: 2
   },
   {
    id: "fund",
    amount: "200",
    fee: 2
   }]
var apitrans = 
  {
   success: true,
   id: "trans",
   tamount: "2000",
   fee: "12"
  }
var apifund =
  {
   success: false,
   id: "fund",
   tamount: "4000",
   fee: "10"
  } 

//inputs scenario 2 how to do same if property name differs
if error, status error, or success false remove obj in sampleobj

var sampleobj=[{
    id: "trans",
    amount: "100",
    fee: 2
   },
   {
    id: "fund",
    amount: "200",
    fee: 2
   },
{ id: "insta", amount: "400", fee: 2 }
]

var apitrans = {success: true,id: "trans",tamount: "2000",fee: "12"}
var apiinsta = { errors: [{code:"error.route.not.supported"}],id: "insta",tamount: "2000",fee: "12"}
var apifund = { status: "error", id: "fund", tamount: "4000", fee: "10" }

var sampleobj=[{
//Expected Output
result: [
  {
    id: "trans",
    amount: "100",
    fee: 2
  }
]```

Answer 1

您可以使用filter()从数组中删除元素。

• 创建一个辅助函数 (func)，它将两个对象作为参数，比较两个对象的 id 属性，并检查其中一个对象的 success 属性他们。
• 然后使用给定数组的 filter() 并将两个给定对象数组放入 [apitrans,apifund]。
• 然后在 [apitrans,apifund] 上使用 some() 方法，并使用 Helper 检查其中任何一个的 id 是否等于当前元素功能。

var arr=[ { id: "trans", amount: "100", fee: 2 }, { id: "fund", amount: "200", fee: 2 } ]

var apitrans = {success: true,id: "trans",tamount: "2000",fee: "12"}
var apifund = { success: false, id: "fund", tamount: "4000", fee: "10" }

const func = (obj1,obj2) => obj1.id === obj2.id && obj2.success

const res = arr.filter(x => [apitrans,apifund].some(a => func(x,a)));
console.log(res)