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powershell - 请解释此 LAN 唤醒脚本的工作原理

转载 作者:行者123 更新时间:2023-12-02 23:31:50 27 4
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几个月前我在博客上发现了这个 PowerShell 代码。它在不使用外部程序的情况下将 LAN 唤醒信号发送到您选择的 MAC 地址。我在博文上发表评论,并要求作者描述脚本背后的逻辑,因为我对此感到好奇。稍后我又回到了博客文章,看看作者是否回复了我的评论。我很惊讶地看到我被重定向到一个页面,其中作者说由于崩溃而丢失了他的博客。我不记得它的细节了,但我想我已经没有那个博客的书签了。

所以现在我想请求 Stack Overflow 的聪明人看看这段代码并向我解释它的逻辑。每一行的评论都会很棒。我很想知道这是如何工作的。它似乎比我发现的其他脚本更强大,因为它可以跨子网工作。不过,我对网络了解不多。

我最好奇的一件事是最后的 for 循环。为什么要多次发送信号?为什么在不同的端口上?但我真的很想知道整个脚本背后的逻辑。

编码:

param (
$targetMac,
$network = [net.ipaddress]::Broadcast,
$subnet = [net.ipaddress]::Broadcast
)
try {
if($network.gettype().equals([string])) {
$network = [net.ipaddress]::Parse($network);
}
if($subnet.gettype().equals([string])) {
$subnet = [net.ipaddress]::Parse($subnet);
}
$broadcast = new-object net.ipaddress (([system.net.ipaddress]::parse("255.255.255.255").address -bxor $subnet.address -bor $network.address))

$mac = [Net.NetworkInformation.PhysicalAddress]::Parse($targetMac.toupper().replace(".",""))

$u = New-Object net.sockets.udpclient
$ep = New-Object net.ipendpoint $broadcast, 0
$ep2 = New-Object net.ipendpoint $broadcast, 7
$ep3 = New-Object net.ipendpoint $broadcast, 9

$payload = [byte[]]@(255,255,255, 255,255,255);
$payload += ($mac.GetAddressBytes()*16)

for($i = 0; $i -lt 10; $i++) {
$u.Send($payload, $payload.Length, $ep) | Out-Null
$u.Send($payload, $payload.Length, $ep2) | Out-Null
$u.Send($payload, $payload.Length, $ep3) | Out-Null
sleep 1;
}
} catch {
$Error | Write-Error;
}

最佳答案

#These are the parameters to the script. The only mandatory param here is the mac address
#[net.ipaddress]::Broadcast will resolve to something like 255.255.255.255
param (
$targetMac,
$network = [net.ipaddress]::Broadcast,
$subnet = [net.ipaddress]::Broadcast
)

#We start the try, catch error handling here.
#if something in try block fails, the catch block will write the error
try {

#This will evaludate to False. Hence, $network will have whatever was passed through params or the default value
#in this case the default value is 255.255.255.255
if($network.gettype().equals([string])) {
$network = [net.ipaddress]::Parse($network);
}

#This will evaludate to False. Hence, $network will have whatever was passed through params or the default value
#in this case the default value is 255.255.255.255
if($subnet.gettype().equals([string])) {
$subnet = [net.ipaddress]::Parse($subnet);
}

#Not sure if this is really required here. But, assuming that the default value for both $network and $subet is 255.255.255.255,
#this will result in $broadcast set to 255.255.255.255
$broadcast = new-object net.ipaddress (([system.net.ipaddress]::parse("255.255.255.255").address -bxor $subnet.address -bor $network.address))

#This again assumes that you had given . as the delimeter in MAC address and removes that from MAC address
$mac = [Net.NetworkInformation.PhysicalAddress]::Parse($targetMac.toupper().replace(".",""))

#Create a new object of type net.sockets.udpclient
$u = New-Object net.sockets.udpclient

#WOL magic packet can be sent on port 0, 7, or 9
#Create a end point for the broadcast address at port 0
$ep = New-Object net.ipendpoint $broadcast, 0

#Create a end point for the broadcast address at port 7
$ep2 = New-Object net.ipendpoint $broadcast, 7

#Create a end point for the broadcast address at port 9
$ep3 = New-Object net.ipendpoint $broadcast, 9

#Create a payload packet
#First, create a byte array
$payload = [byte[]]@(255,255,255, 255,255,255);

#add the mac address to the above byte array
$payload += ($mac.GetAddressBytes()*16)

#Send 10 magic packets for each port number or end point created above.
#one is more than enough. If everything is congfigured properly
for($i = 0; $i -lt 10; $i++) {
$u.Send($payload, $payload.Length, $ep) | Out-Null
$u.Send($payload, $payload.Length, $ep2) | Out-Null
$u.Send($payload, $payload.Length, $ep3) | Out-Null
sleep 1;
}
} catch {
#catch block catches any error from try block
$Error | Write-Error;
}

关于powershell - 请解释此 LAN 唤醒脚本的工作原理,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5144505/

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