javascript - 为什么我的函数不被识别？ JavaScript

Question

好的，所以我已经大大减少了代码，现在有点不同，但它做了同样的事情。

游戏套接字.js

//Start Fight Action
socket.on("fight", () => {
 combat(io, socket, app);
});

action-timer.js

const combat = require("./combat/combat");
module.exports = (type, io, socket, app) => {
  if (type == "combat") {
    app.online.actionTime = setTimeout(() => {
      combat(io, socket, app);
    }, 1000);
  } else if (type == "tradeskill") {
  }
};

combat.js

const startAction = require("../action-timer");
module.exports = (io, socket, app) => {
  //Run another combat
  console.log("COMBAT");
  startAction("combat", io, socket, app);
};

错误:

action-timer.js:5
      combat(io, socket, app);
      ^

TypeError: combat is not a function
    at Timeout.app.online.actionTime.setTimeout [as _onTimeout] (C:\Users\wjpop\Desktop\kog\funcs\action-timer.js:5:7)
    at listOnTimeout (timers.js:327:15)
    at processTimers (timers.js:271:5)

Answer 1

我想通了，奇怪的是我必须这样做，因为通常不需要这样做，但 action-timer.js 应该像这样:

module.exports = (type, io, socket, app) => {
  const combat = require("./combat/combat");
  if (type == "combat") {
    app.online.actionTime = setTimeout(() => {
      combat(io, socket, app);
    }, 1000);
  } else if (type == "tradeskill") {
  }
};