javascript - 返回值返回为未定义

Question

我正在尝试为 Illustrator 编写一个脚本，该脚本将从对象中读取我需要的颜色，然后在需要的地方用该颜色填充模板。它一直返回为未定义。我对 Javascript 还很陌生，你知道我做错了什么吗？

我尝试返回为 newCMYKColor[stockColor] 、 newCMYKColor[stockColors] 并返回 stockColor[newCMYKColor]

convertRoofColorToCMYK = function(stockColor) {
  var newCMYKColor = new CMYKColor(),
    stockColors = {
      BlackPoly: [80, 72, 68, 100],
      LightBlue: [100, 43, 0, 30],
      DarkBluePoly: [95, 74, 7, 44],
      PurplePoly: [82, 98, 0, 12],
      GreenPoly: [90, 12, 95, 40],
      YellowPoly: [0, 19, 89, 0],
      EcruPoly: [6, 13, 41, 4],
      OrangePoly: [0, 73, 98, 0],
      RedPoly: [7, 100, 82, 26],
      GreyPoly: [10, 4, 4, 14],
      WhitePoly: [0, 0, 0, 0]
    };
  try {
    newCMYKColor.cyan = stockColors[stockColor][0];
    newCMYKColor.magenta = stockColors[stockColor][1];
    newCMYKColor.yellow = stockColors[stockColor][2];
    newCMYKColor.black = stockColors[stockColor][3];
  } catch (e) {
    newCMYKColor.cyan = 0;
    newCMYKColor.magenta = 0;
    newCMYKColor.yellow = 0;
    newCMYKColor.black = 0;
  }
  return newCMYKColor;
};

roofColorCMYK = convertRoofColorToCMYK(Clipboard.roof_color);

if (!roofColorCMYK == undefined) {
  if (app.activeDocument.Layers["Tent Pieces"] &&
    app.activeDocument.Layers["Tent Pieces"].Layers["Roof Composite"]) {
    for (i = 0; i < app.activeDocument.Layers["Tent Pieces"].Layers["Roof Composite"].pathItems.length; i++) {
      app.activeDocument.Layers["Tent Pieces"].Layers["Roof Composite"].pathItems[i].fillColor = roofColorCMYK;
    } else {
      alert("sorry we are not able to fill the tent roof with the " +
        Clipboard.roof_color + " color.")
    }

在我添加 else/if 语句之前，它告诉我在 if (app.activeDocument.Layers["Tent Pieces"] && app.activeDocument.Layers["Tent Pieces"].Layers["处未定义屋顶复合 Material "])。添加 else/if 语句后，它每次都会给我警报。

Answer 1

请查看 MDN 的 try catch block 规范。 https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/try...catch .

您必须记住，在 try catch block 之后不会执行任何代码。

我建议您这样更改代码:

try {
    newCMYKColor.cyan = stockColors[stockColor][0];
    newCMYKColor.magenta = stockColors[stockColor][1];
    newCMYKColor.yellow = stockColors[stockColor][2];
    newCMYKColor.black = stockColors[stockColor][3];

    return newCMYKColor;
  } catch (e) {
    newCMYKColor.cyan = 0;
    newCMYKColor.magenta = 0;
    newCMYKColor.yellow = 0;
    newCMYKColor.black = 0;

    return newCMYKColor;
  }

或者在最后使用finally block (finally中的代码总是执行之前发生的事情)。

try {
    newCMYKColor.cyan = stockColors[stockColor][0];
    newCMYKColor.magenta = stockColors[stockColor][1];
    newCMYKColor.yellow = stockColors[stockColor][2];
    newCMYKColor.black = stockColors[stockColor][3];
  } catch (e) {
    newCMYKColor.cyan = 0;
    newCMYKColor.magenta = 0;
    newCMYKColor.yellow = 0;
    newCMYKColor.black = 0;
  } finaly {
    return newCMYKColor;
  }