python-3.x - 如何在Elasticsearch中计算每个 token 的总数

Question

我有一个请求Elastic

{  
   "query":{  
      "bool":{  
         "must":[  
            {  
               "query_string":{  
                  "query":"something1 OR something2 OR something3",
                  "default_operator":"OR"
               }
            }
         ],
         "filter":{  
            "range":{  
               "time":{  
                  "gte":date
               }
            }
         }
      }
   }
}

我想在一个请求中使用 flex 搜索来计算所有文档中每个 token 的计数，例如:

something1: 26 documents
something2: 12 documents
something3: 1 documents

Answer 1

假设 token 与枚举不类似(即受约束的一组特定值(例如状态名称)，这会使正确的映射使terms aggregation成为您的最佳选择)，我认为与filters aggregation最接近的是:

POST your-index/_search
{
  "query":{  
    "bool":{  
      "must":[  
      {  
        "query_string":{  
          "query":"something1 OR something2 OR something3",
          "default_operator":"OR"
         }
      }
      ],
      "filter":{  
        "range":{  
          "time":{  
            "gte":date
          }
        }
      }
    }
  },
  "aggs": {
    "token_doc_counts": {
      "filters" : {
        "filters" : {
          "something1" : { 
            "bool": { 
              "must": { "query_string" : { "query" : "something1" } }, 
              "filter": { "range": { "time": { "gte": date } } } 
            }
          },
          "something2" : { 
            "bool": { 
              "must": { "query_string" : { "query" : "something2" } }, 
              "filter": { "range": { "time": { "gte": date } } } 
            }
          },
          "something3" : { 
            "bool": { 
              "must": { "query_string" : { "query" : "something3" } }, 
              "filter": { "range": { "time": { "gte": date } } } 
            }
          }
        }
      }
    } 
  }
}

响应如下所示:

{
  "took": 9,
  "timed_out": false,
  "_shards": ...,
  "hits": ...,
  "aggregations": {
    "token_doc_counts": {
      "buckets": {
        "something1": {
          "doc_count": 1
        },
        "something2": {
          "doc_count": 2
        },
        "something3": {
          "doc_count": 3
        } 
      } 
    } 
  }
}