hibernate - HQL 批量插入

Question

我将 postgresql 与 hibernate 结合使用，我想将数据从模板表批量插入到另一个模板表中。如何在 native 查询中做到这一点对我来说很清楚，但在 HQL 中我真的不知道如何达到我的预期结果。我使用 http://docs.jboss.org/hibernate/core/3.3/reference/en/html/batch.html#batch-direct 中的语法创建我的查询。

@NamedQuery(name="Tile.bulkLoadLevel", query="INSERT INTO Tile (x, y, game, tileOverlay, startTile, blockWalkable, sightBlocking)" +
        " SELECT t.x, t.y, :game as game, t.tileOverlay, t.startTile, t.blockWalkable, t.sightBlocking from TemplateQuestTile t")

我的谢玛:

CREATE TABLE tile
(
   x integer NOT NULL,
   y integer NOT NULL,
   blockwalkable boolean NOT NULL,
   sightblocking boolean NOT NULL,
   starttile boolean NOT NULL,
   imagepath character varying(255) NOT NULL,
   gameid bigint NOT NULL,
   CONSTRAINT tile_pkey PRIMARY KEY (gameid, x, y)
 );

简化我的模板:

   CREATE TABLE templatequesttile
   (
     x integer NOT NULL,
     y integer NOT NULL,
     blockwalkable boolean NOT NULL,
     sightblocking boolean NOT NULL,
     starttile boolean NOT NULL,
     imagepath character varying(255) NOT NULL,
     questname character varying(255) NOT NULL,
     CONSTRAINT templatequesttile_pkey PRIMARY KEY (questname, questseries, x, y)
   )

我收到以下错误:

ERROR (SessionFactoryImpl.java:435) - Error in named query: Tile.bulkLoad
org.hibernate.QueryException: number of select types did not match those for insert [INSERT INTO Tile (x, y,    game, tileOverlay, startTile, blockWalkable, sightBlocking) SELECT t.x, t.y, :game, t.tileOverlay, t.startTile, t.blockWalkable, t.sightBlocking from net.hq.model.TemplateQuestTile t]
at org.hibernate.hql.ast.tree.IntoClause.validateTypes(IntoClause.java:115)
at org.hibernate.hql.ast.tree.InsertStatement.validate(InsertStatement.java:57)
at org.hibernate.hql.ast.HqlSqlWalker.postProcessInsert(HqlSqlWalker.java:715)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.insertStatement(HqlSqlBaseWalker.java:519)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:261)

游戏是一个实体，具有由序列生成的长标识符。

正如您所看到的，游戏不在我的模板表中，因此我需要强制将游戏 ID 放入我的查询中。有谁知道如何做到这一点？

预先感谢您的宝贵时间，此致米

PS:我如何调用查询:

Query query = em.createNamedQuery("Tile.bulkLoadLevel");
query.setParameter("game", game.getGameid());
int copyiedEntities = query.executeUpdate();

实体:

public class Tile implements Serializable{

@Id
private int x;
@Id
private int y;
@Id
@ManyToOne
@JoinColumn(name="gameid")
private Game game;

PS: Actor 阵容也不起作用。

java.lang.ExceptionInInitializerError at net.hq.process.db.PersistenceTest.setUp(PersistenceTest.java:58) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44) at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15) at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41) at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:27) at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31) at org.junit.runners.ParentRunner.run(ParentRunner.java:236) at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:49) at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197) Caused by: java.lang.NullPointerException at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at org.hibernate.util.ReflectHelper.classForName(ReflectHelper.java:192) at org.hibernate.type.TypeFactory.heuristicType(TypeFactory.java:279) at org.hibernate.type.TypeFactory.heuristicType(TypeFactory.java:264) at org.hibernate.hql.ast.util.SessionFactoryHelper.findFunctionReturnType(SessionFactoryHelper.java:400) at org.hibernate.hql.ast.util.SessionFactoryHelper.findFunctionReturnType(SessionFactoryHelper.java:392) at org.hibernate.hql.ast.tree.MethodNode.dialectFunction(MethodNode.java:103) at org.hibernate.hql.ast.tree.MethodNode.resolve(MethodNode.java:78) at org.hibernate.hql.ast.HqlSqlWalker.processFunction(HqlSqlWalker.java:979) at org.hibernate.hql.antlr.HqlSqlBaseWalker.functionCall(HqlSqlBaseWalker.java:2529) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExpr(HqlSqlBaseWalker.java:2129) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExprList(HqlSqlBaseWalker.java:1983) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectClause(HqlSqlBaseWalker.java:1515) at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:586) at org.hibernate.hql.antlr.HqlSqlBaseWalker.insertStatement(HqlSqlBaseWalker.java:510) at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:261) at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:254) at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:185) at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136) at org.hibernate.engine.query.HQLQueryPlan.(HQLQueryPlan.java:101) at org.hibernate.engine.query.HQLQueryPlan.(HQLQueryPlan.java:80) at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:98) at org.hibernate.impl.SessionFactoryImpl.checkNamedQueries(SessionFactoryImpl.java:562) at org.hibernate.impl.SessionFactoryImpl.(SessionFactoryImpl.java:424) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1385) at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:954) at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:891) at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:57) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:48) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:32) at net.hq.util.Db.(Db.java:7) ... 17 more

Answer 1

尝试:

INSERT INTO Tile (x, y, game, tileOverlay, startTile, blockWalkable, sightBlocking) SELECT t.x, t.y, cast(:game as Game), t.tileOverlay, t.startTile, t.blockWalkable, t.sightBlocking from TemplateQuestTile t")

和

query.setEntity("game", game);

我假设您还有一个名为 Tile 的类，并且 x、y、tileOverlay... 是该类的属性。来自 hibernate 引用文档:“INSERT 语句的伪语法是:INSERT INTO EntityName properties_list选择语句”。

关于强制转换函数，“cast(... as ...)，其中第二个参数是 Hibernate 类型的名称”，所以它应该可以工作。

我没有尝试使用实体，但它对于简单类型(字节、整数...)运行良好。