powershell - 将字符串分成两个数组

Question

我有一个像下面的字符串

abc-ijk-90-hortons-899-mnb-8037-POI-AS-QWE-ZXC-TYUIOP-KEW-197.127.255.0/23
abc-ijk-90-hortons-975-mnb-8024-POI-AS-QWE-ZXC-TYUIOP-KUYW-198.157.150.0/23
abc-ijk-90-hortons-356-mnb-8022-POI-AS-QWE-ZXC-TYUIOP-JHT-199.127.132.0/23

我想把字符串分成

c1= {8037,8024,8022}
c2= {POI-AS-QWE-ZXC-TYUIOP-KEW-197.127.255.0/23,POI-AS-QWE-ZXC-TYUIOP-KUYW-198.157.150.0/23,POI-AS-QWE-ZXC-TYUIOP-JHT-199.127.132.0/23}

c3应该显示如下

Number  Name
8037    POI-AS-QWE-ZXC-TYUIOP-KEW-197.127.255.0/23
8024    POI-AS-QWE-ZXC-TYUIOP-KUYW-198.157.150.0/23
8022    POI-AS-QWE-ZXC-TYUIOP-JHT-199.127.132.0/23

Answer 1

在-处拆分字符串的行，但将拆分限制为8次，
因此，将POI-...保持在一行的最后一行

中

然后选择从零开始的索引[6,7]放入vars $ Number，$ Name

构建这两个变量的[PSCustomObject]。

最终从$ c3的属性中构建$ c1，$ c2

$string = @"
abc-ijk-90-hortons-899-mnb-8037-POI-AS-QWE-ZXC-TYUIOP-KEW-197.127.255.0/23
abc-ijk-90-hortons-975-mnb-8024-POI-AS-QWE-ZXC-TYUIOP-KUYW-198.157.150.0/23
abc-ijk-90-hortons-356-mnb-8022-POI-AS-QWE-ZXC-TYUIOP-JHT-199.127.132.0/23
"@ -split '\r?\n'

$c3 = foreach ($line in $string){
    $Number,$Name= ($line -split '-',8)[6,7]
    [PSCustomObject]@{
        Number = $Number
        Name   = $Name
    }
}
# it's not quite clear what type you expect $c1,$c2 to be.
# a simple joined string
$c1 = '{'+($c3.Number -join ',')+'}'
$c2 = '{'+($c3.Name   -join ',')+'}'

$c1;$c2;$c3

样本输出:

{8037,8024,8022}
{POI-AS-QWE-ZXC-TYUIOP-KEW-197.127.255.0/23,POI-AS-QWE-ZXC-TYUIOP-KUYW-198.157.150.0/23,POI-AS-QWE-ZXC-TYUIOP-JHT-199.127.132.0/23}

Number Name
------ ----
8037   POI-AS-QWE-ZXC-TYUIOP-KEW-197.127.255.0/23
8024   POI-AS-QWE-ZXC-TYUIOP-KUYW-198.157.150.0/23
8022   POI-AS-QWE-ZXC-TYUIOP-JHT-199.127.132.0/23