javascript - 如何迭代数组中的值以匹配对象中的值并返回相应的对象？

Question

这个问题已经有答案了:

How to filter object array based on attributes? (21 个回答)

已关闭 4 年前。

我尝试在另一个包含大量对象的数组中搜索我在数组中获得的任何值。我尝试使用 lodash，但 vanilla 也可以。

我的引用数组是这样的:

let array1 = ["value1", "value2", "value8", "value9"]

我想在这个对象数组中找到这些值:

let array2 = [{
  key1: xxx
  key2: value1
  key3: xxxx
}, {
  key1: value2
  key2: xxxx
  key3: xxxx
}, {
  key1: xxx
  key2: xxx
  key3: value3
}]

我已经尝试过

let finalData: []

let filterData = _.filter(array2, array1);
this.finalData = filterData

我希望返回一个包含所有匹配对象的数组:

[{
  key1: xxx
  key2: value1
  key3: xxxx
}, {
  key1: xxx
  key2: value2
  key3: xxxx
}]

我总是得到一个空数组。我需要为每种方法组合一个来做到这一点吗？

奖励:如果它可以返回一个包含未找到值(value8、value9)的数组的错误，这将是锦上添花。

Answer 1

let array1 = ["value1", "value2", "value8", "value9"];
let array2 = [
  {
    "key1": "xxx",
    "key2": "value1",
    "key3": "xxxx"
  }, {
    "key1": "xxx",
    "key2": "value2",
    "key3": "xxxx"
  },
  {
    "key1": "xxx",
    "key2": "value3",
    "key3": "xxxx"
  }
];

// copy the original array1
let noMatch = [...array1];

// iterate (and filter) through every element
// that array2 contains
let match = array2.filter(elem => {
  // iterate through every key in the element
  for (const key in elem) {
    // check if array1 has the value
    const found = array1.find(e => e === elem[key]);
    if (found) {
      // remove from noMatch the matched value
      noMatch = noMatch.filter(e => e !== found);
      // found
      return true;
    }
  }
  // Not found
  return false;
});

// matched elements
console.log('match', match);
// values that didn't match any element
console.log('noMatch', noMatch);