javascript - 根据键合并两个对象数组

Question

我有两个数组:

数组1:

[
  { id: "abdc4051", date: "2017-01-24" }, 
  { id: "abdc4052", date: "2017-01-22" }
]

和数组 2:

[
  { id: "abdc4051", name: "ab" },
  { id: "abdc4052", name: "abc" }
]

我需要根据id合并这两个数组并得到:

[
  { id: "abdc4051", date: "2017-01-24", name: "ab" },
  { id: "abdc4052", date: "2017-01-22", name: "abc" }
]

如何在不迭代 Object.keys 的情况下做到这一点？

Answer 1

你可以这样做 -

let arr1 = [
    { id: "abdc4051", date: "2017-01-24" },
    { id: "abdc4052", date: "2017-01-22" }
];

let arr2 = [
    { id: "abdc4051", name: "ab" },
    { id: "abdc4052", name: "abc" }
];

let arr3 = arr1.map((item, i) => Object.assign({}, item, arr2[i]));

console.log(arr3);

<小时/>

如果 arr1 和 arr2 的顺序不同，请使用以下代码:

let arr1 = [
  { id: "abdc4051", date: "2017-01-24" }, 
  { id: "abdc4052", date: "2017-01-22" }
];

let arr2 = [
  { id: "abdc4051", name: "ab" },
  { id: "abdc4052", name: "abc" }
];

let merged = [];

for(let i=0; i<arr1.length; i++) {
  merged.push({
   ...arr1[i], 
   ...(arr2.find((itmInner) => itmInner.id === arr1[i].id))}
  );
}

console.log(merged);

如果 arr1 和 arr2 顺序相同，则使用此选项

let arr1 = [
  { id: "abdc4051", date: "2017-01-24" }, 
  { id: "abdc4052", date: "2017-01-22" }
];

let arr2 = [
  { id: "abdc4051", name: "ab" },
  { id: "abdc4052", name: "abc" }
];

let merged = [];

for(let i=0; i<arr1.length; i++) {
  merged.push({
   ...arr1[i], 
   ...arr2[i]
  });
}

console.log(merged);