javascript - 过滤数组内的对象

Question

我需要删除整个未通过的对象

这是数组

const array = [{
    course: 1,
    list: [{
        id: 1,
        name: "john",
        code: true
      },
      {
        id: 1,
        name: "maria",
        code: true
      },
    ]
  },
  {
    course: 2,
    list: [{
        id: 3,
        name: "rose"
      },
      {
        id: 4,
        name: "mark",
        code: true
      }
    ]
  }
]

我需要的是删除没有 code:true 的 obj，然后得到这个

const array = [{
    course: 1,
    list: [{
      id: 1,
      name: "john",
      code: true
    }, ]
  },
  {
    course: 2,
    list: [{
      id: 1,
      name: "mark",
      code: true
    }]
  }
]

我尝试在过滤器内制作 map ，但它根本不起作用

const remove = array.filter(function(lines) {
  return lines.map(line => line.list.map(list => list.code))
});

Answer 1

可以通过数组进行映射，然后复制特定项的所有属性，并单独对列表属性进行过滤。

const array = [{
    course: 1,
    list: [{
        id: 1,
        name: "john",
        code: true
      },
      {
        id: 1,
        name: "maria",
        code: true
      },
    ]
  },
  {
    course: 2,
    list: [{
        id: 3,
        name: "rose"
      },
      {
        id: 4,
        name: "mark",
        code: true
      }
    ]
  }
]

const filter = arr => arr.map(arrItem => ({ 
     ...arrItem,
    list: arrItem.list.filter( listItem => listItem.code )
  })
)

console.log( filter(array) )