javascript - 如何输出多个值(折扣)？

Question

我试图了解如何返回多个值。现在，我的代码设置为为任何具有一个兑换代码的代码返回单个对象(redeemDisc)。我的问题是，如果一个代码有多个兑换代码，它只会返回“多个折扣”。我试图了解如何将“redeemDisc”存储在数组中，以便如果有多个折扣我可以返回所有折扣

redeemCode({ userUuid, code }) {
let error;
let locationId;
return this.models.BusinessLocation.findOne({
  where: {
    code: code,
    deleted: false
  }
}).then(loc => {

  if (loc === null)
  {
    error = 'Invalid Code';
    return;
  }
  locationId = loc.id;
  return this.models.OfferLocation.findAndCountAll({
    where: {
      locationId: loc.id
    }
  })
}).then(async offerLocs => {

    if (offerLocs.length === 0)
    {
      return "Zero Discounts";
    }
    let count = 0;
    let offer;
    let i;
    for ( i = 0; i < offerLocs.rows.length;i++)
    {
        let offerLoc = offerLocs.rows[i];
        offer = await this.models.Discount.findOne({
          where: {
            id: offerLoc.offerId
          }
        });

        if (!offer.active || offer.deleted)
        {
          continue;
        }

        count++;
    }

    console.log('redeeemCode -service (offer count)', count) ;       
    console.log('redeeemCode -service (offer )', JSON.stringify(offer)) ;       

    if (count > 1)
    {
      return 'multiple discounts';
    }
    if (count === 0)
    {
      return 'zero discounts';
    }

    // have a single offer - claim

    return this.redeemDisc(
      { discountId: offer.id , 
        userUuid: userUuid, 
        code: code, 
        locationId: locationId
      }).then(redeemed => {
        return redeemed;
        }
        )


})

}

对于单个折扣，它返回 JSON 格式的

"redeemed": {
    "createdAt": "2019-10-27T23:54:14.031Z",
    "updatedAt": "2019-10-27T23:54:14.031Z",
    "id": "143751f0-f915-11e9-8107-658322eb948c",
    "UserUuid": "b136ccd9-0783-482d-956b-7082286051b3",
    "DiscountId": "97cfdf90-3ee0-11e9-b720-c1f2606cbbd2",
    "BusinessId": "978a7220-3ee0-11e9-b720-c1f2606cbbd2",
    "locationId": "97cf1c40-3ee0-11e9-b720-c1f2606cbbd2"
}

我需要了解如何返回与给定代码关联的所有折扣，因此预期输出为

兑换:{ ... },赎回:{...}，...

Answer 1

由于您有与一个代码相关的多个优惠，因此您必须使用优惠数组而不是变量，并且您应该将优惠的每个详细信息存储在该优惠数组中。

let offer = [];
let i;
for ( i = 0; i < offerLocs.rows.length;i++)
{
    let offerLoc = offerLocs.rows[i];
    offer[count] = await this.models.Discount.findOne({
      where: {
        id: offerLoc.offerId
      }
    });

    if (!offer.active || offer.deleted)
    {
      continue;
    }

    count++;
}

现在您可以像这样存储并返回折扣数组。

var discount = []
for(let j =0; j<offer.length; ++j) {
   let redeem = await this.redeemDisc(
                  { discountId: offer.id , 
                    userUuid: userUuid, 
                    code: code, 
                    locationId: locationId
                  })
  discount.push({"redeemed": redeem})                 

}

return discount;