Terraform 资源继承

Question

有没有办法声明要继承的抽象资源？

示例:

resource "digitalocean_droplet" "worker_abstract" {
  abstract = true // ???

  name = "swarm-worker-${count.index}"
  tags = [
    "${digitalocean_tag.swarm_worker.id}"
  ]

  // other config stuff

  provisioner "remote-exec" {
    //...
  }
}

然后使用声明的资源和覆盖的变量:

resource "worker_abstract" "worker_foo" {
  count = 2
  name = "swarm-worker-foo-${count.index}"
  tags = [
    "${digitalocean_tag.swarm_worker.id}",
    "${digitalocean_tag.foo.id}"
  ]
}

resource "worker_abstract" "worker_bar" {
  count = 5
  name = "swarm-worker-bar-${count.index}"
  tags = [
    "${digitalocean_tag.swarm_worker.id}"
    "${digitalocean_tag.bar.id}"
  ]
}

Answer 1

这可能比您提议的解决方案更“冗长”，但这听起来像是 modules in 0.12 的完美用例。 .

您可以创建一个模块，例如在文件 worker/main.tf

中

variable "instances" {
  type = number
}

variable "name" {
  type = string
}

variable "tags" {
  type    = list(string)
  default = []
}

resource "digitalocean_droplet" "worker" {
  count = var.instances

  name = "swarm-worker-${var.name}-${count.index}"
  tags = var.tags

  // other config stuff

  provisioner "remote-exec" {
    //...
  }
}

然后你就可以像你的示例一样使用你的模块(假设从上面的目录worker)

module "worker_foo" {
  source = "./worker"

  instances = 2
  name = "foo"
  tags = [
    "${digitalocean_tag.swarm_worker.id}",
    "${digitalocean_tag.foo.id}"
  ]
}

module "worker_bar" {
  source = "./worker"

  instances = 5
  name = "bar"
  tags = [
    "${digitalocean_tag.swarm_worker.id}"
    "${digitalocean_tag.bar.id}"
  ]
}