javascript - 如何将函数的返回值作为参数传递？

Question

我有很多类似于 FunctionOne 的函数。它们之间的区别是 Five = this.methodTwo(二，三，四，五)。我不想重复代码。为此，如何将函数的返回值作为参数传递？

class MyClass {
    FunctionOne(one, two, three, four, five) {
        //some code here
        one = "my one";
        two = "my two";
        five = this.FunctionTwo(two, three, four, five); //How can I pass this as parameter
        one[five] = "something";
        return one;
    }
    FunctionThree(one, two, three, four, five) {
        //some code here
        one = "my one";
        two = "my two";
        five = this.FunctionFour(two, three, four, five); //Everything in FunctionThree is same as FunctionOne except this statement
        one[five] = "something";
        return one;
    }

    FunctionTwo(two, three, four, five) {
        //some code
        return five;
    }
}

Answer 1

解决这个问题的一种方法是将函数作为另一个参数。

与 FunctionOne、FunctionTwo 等类似，您可以使用 FunctionX 来完成常见工作并调用传递的函数，该函数作为参数可以由调用者更改。

看起来像这样:

// added 'fn', the function to call, as the sixth parameter
FunctionX(one, two, three, four, five, fn) {
    //some code here
    one = "my one";
    two = "my two";
    five = fn(two, three, four, five);
    one[five] = "something";
    return one;
}

现在您可以在其他地方调用它，例如:

let x = FunctionX(h, i, j, k, l, FunctionOne);