javascript - while循环中非​​法的break语句

Question

这个问题已经有答案了:

Short circuit Array.forEach like calling break (31 个回答)

已关闭 去年。

很抱歉重复别人的问题。我已经看过这些答案，但仍在努力完成我需要的事情。

我想继续尝试我的密码生成器功能，直到它给我一个包含符号、数字和大写字母的密码生成器功能。

你能帮忙吗？

while (true) {
  let trialPassword = randomPassGen(10)

  trialPassword.forEach((letter)=>{
    if (!upperLetters.includes(letter)){
      return
    } else if (!symbols.includes(letter)) {
      return
    } else if (!numbers.includes(letter)) {
      return
    } else {
      break
    }
  })
  console.log(trialPassword)
}

编辑:这是我的密码生成器的完整代码。这次尝试使用 for 循环，但仍然没有成功。谢谢大家!

const upperLetters = [
  'A','B','C','D','E','F','G','H','I','J','K','L','M','N','P','Q','R','S','T','U','V','W','X','Y','Z'
]

const lowerLetters = []

// build lowerLetters from upper skipping lowecase L which could be seen as a 1
upperLetters.forEach((letter)=>{
  if(letter !== 'L'){
    lowerLetters.push(letter.toLowerCase())
  }
})
// skips letter l

const numbers = [0,1,2,3,4,5,6,7,8,9]

const symbols = [
  '!', '@', ';', ':', '$', '£', '#', '[', ']', '?', '<', '>'
]

const allChars = []

symbols.forEach((sym)=>{
  allChars.push(sym)
})

numbers.forEach((num)=>{
  allChars.push(num)
})

lowerLetters.forEach((lowLet)=>{
  allChars.push(lowLet)
})

upperLetters.forEach((upLet)=>{
  allChars.push(upLet)
})

const randomPassGen = (passLength) => {
  passArr = []

  for (let i = 0; i <= passLength; i++) {
    let r = Math.floor(Math.random() * allChars.length);
    passArr.push(allChars[r])
  }
    return passArr
  }



while (true) {
  let trialPassword = randomPassGen(chosenLength)

  for (let i = 0; i <=trialPassword.length; i++){
    let l = trialPassword[i]
    if(!upperLetters.includes(l)){
      continue
    } else if (!symbols.includes(l)){
      continue
    } else if (!numbers.includes(l)){
      continue
    } else {
      console.log(trialPassword)
      break
    }
  }
}

Answer 1

如果您的目的是退出 while 循环，请使用变量作为标志，并在 forEach 循环中设置该标志:

var keepgoing=true;
while (keepgoing) {
  let trialPassword = randomPassGen(10)

  trialPassword.forEach((letter)=>{
    if (!upperLetters.includes(letter)){
      keepgoing=false; return;
    } else if (!symbols.includes(letter)) {
      keepgoing=false; return;
    } else if (!numbers.includes(letter)) {
      keepgoing=false; return;
    } else {
      keepgoing=false;
    }
  })
  console.log(trialPassword)
}

此外，if/else if 链是不好的编码风格，但那是另一个话题了。