php - 使用PHP正则表达式计算ElasticSearch的结果

Question

当ElasticSearch返回以下行时，我想保存计数结果:

{"took":13,"timed_out":false,"_shards":{"total":5,"successful":5,"failed":0},"hits":{"total":2242,"max_score":1.0,"hits":[{"_index":"

我希望将总结果保存到变量中，但是我找不到保存“2242”的良好正则表达式规则。

Answer 1

为什么您认为需要正则表达式？只需使用 json_decode 并像这样访问它；对于此示例，关闭了JSON:

$raw_json = '{"took":13,"timed_out":false,"_shards":{"total":5,"successful":5,"failed":0},"hits":{"total":2242,"max_score":1.0,"hits":[{"_index":"999999"}]}}';

$decoded_json = json_decode($raw_json);

echo '<pre>';
print_r($decoded_json);
echo '</pre>';

输出将是这样的:

stdClass Object
(
    [took] => 13
    [timed_out] => 
    [_shards] => stdClass Object
        (
            [total] => 5
            [successful] => 5
            [failed] => 0
        )

    [hits] => stdClass Object
        (
            [total] => 2242
            [max_score] => 1
            [hits] => Array
                (
                    [0] => stdClass Object
                        (
                            [_index] => 999999
                        )

                )

        )

)

然后知道您只是像这样访问 total下的 hits:

$hits_total = $decoded_json->hits->total;

echo $hits_total;

或者，如果您不容易解析对象，只需将 json_decode的第二个参数设置为 true即可返回数组。

$decoded_json = json_decode($raw_json, true);

然后像这样访问它:

$hits_total = $decoded_json['hits']['total'];

echo $hits_total;