javascript - 如何在 Google Chrome 扩展程序中发送 ajax 请求？

Question

我正在尝试在 chrome 扩展中发送 ajax 请求。我的 list :

{
  "name": "example",
  "version": "0.0.1",
  "description": "Chrome Extension's message passing example",
  "browser_action": {
    "default_icon": "images/get_started32.png",
    "default_popup": "popup.html"
  },
  "background": {
    "scripts": ["background.js"]
  },
  "content_scripts":[{
    "matches":["http://*/*", "https://*/*"],
    "js":["popup.js"]
  }],
  "permissions": [
    "background","webRequest","webRequestBlocking","webNavigation","tabs","notifications","https://example.com/*"
  ],
  "manifest_version": 2
}

背景.js

chrome.runtime.onMessage.addListener((msg, sender, sendResponse) => {
  if (msg.foo === 'bar') {
    var url = "https://example.com/path";
      fetch(url)
        .then(response => sendResponse(response.text()))
        .catch(error => handleError(error))
      return true;  // Will respond asynchronously.
  }
});

function handleError(error){
  console.log(error);
}

popup.js

chrome.runtime.sendMessage({foo: 'bar'}, response => {
  alert(JSON.stringify(response));
});

即使该网址有数据，弹出数据也会以“{}”形式返回。我做错了什么？

Answer 1

自response.text() returns a Promise ，您需要在发送之前添加另一个 then 来解析 Promise:

chrome.runtime.onMessage.addListener((msg, sender, sendResponse) =>
{
    if (msg.foo === 'bar')
    {
        var url = "https://example.com/path";
        fetch(url)
            .then(response => response.text()
                .then(t => sendResponse(t))
            .catch(error => handleError(error))
        return true;  // Will respond asynchronously.
    }
});