powershell - 在 Powershell 中比较 System.Version

Question

我有一个案例，我必须根据比较版本在脚本中做出决定
考虑这个例子:

PS C:\>
[version]$SomeVersion='1.1.1'
[version]$OtherVersion='1.1.1.0'

PS C:\> $SomeVersion

Major  Minor  Build  Revision
-----  -----  -----  --------
1      1      1      -1      

PS C:\> $OtherVersion

Major  Minor  Build  Revision
-----  -----  -----  --------
1      1      1      0       

PS C:\>$SomeVersion -ge $OtherVersion
False

我想在比较 System.Version 类型的对象时省略修订
我找不到任何理智的方法来做到这一点。
有没有？

注意 - 我试过这样做:

PS C:\> ($scriptversion |select major,minor,build) -gt ($currentVersion|select major,minor,build)

Cannot compare "@{Major=1; Minor=1; Build=1}" to "@{Major=1; Minor=1; 
Build=1}" because the objects are not the same type or the object "@{Major=1; 
Minor=1; Build=1}" does not implement "IComparable".
At line:1 char:1
+ ($scriptversion |select major,minor,build) -gt ($currentVersion |sele ...
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo          : NotSpecified: (:) [], ExtendedTypeSystemException
+ FullyQualifiedErrorId : PSObjectCompareTo

当我尝试用 0 覆盖修订号时，它表示它是只读属性...
我有一个解决方法但我希望用 system.version 做得更好

Answer 1

使用 three argument System.Version constructor使用相关属性创建新实例:

[Version]::new($scriptversion.Major,$scriptversion.Minor,$scriptversion.Build) -gt [Version]::new($currentVersion.Major,$currentVersion.Minor,$currentVersion.Build)

或者您可以使用 New-Object 进行详细说明:

$NormalizedScriptVersion = New-Object -TypeName System.Version -ArgumentList $scriptversion.Major,$scriptversion.Minor,$scriptversion.Build
$NormalizedCurrentVersion = New-Object -TypeName System.Version -ArgumentList $currentVersion.Major,$currentVersion.Minor,$currentVersion.Build

$NormalizedScriptVersion -gt $NormalizedCurrentVersion 

使用您认为更易于维护的任何一个。