javascript - 如何在 native react 中调用递归异步函数？

Question

我想检查特定的 bool 函数是否返回 true。如果是这样，请运行随机数生成器并尝试再次检查 bool 函数。如此反复，直到结果为假。然后停止递归并结束函数。

这是我想要做的一个想法，但我不太确定如何一次又一次地调用随机数，直到 hasDataBeenSeen() 返回 false。请帮忙!

    async hasDataBeenSeen(key) {
       var obj = userData[];  //pre-populated string array

       if (obj.indexOf(key) > -1) {
         //In the array!
         return true
       } 
       else {
         //Not in the array
         return false
       }
    }
    catch (err) {
      console.log(err)
    }
  }

 async executeFunction() {  
    const dbIndex = this.getUniqueRandomNumber(this.state.ArrayLength); //gets a random +ve integer

    //Check if this string in the array has been seen (return true or false)
    if(!await this.hasDataBeenSeen(this.state.Data[dbIndex].Key))  ///this.state.Data[] is an array. ALSO if the string is not in the array (i.e. false) then we have what we need and finish the function 
    {
        if(dbIndex != null){
              this.setState({ finalString: this.state.Data[dbIndex].Key });   //Set the string locally and finish function
        }     
    } 
    else
    {
       //call the random number function again ???
        this.getUniqueRandomNumber(this.state.ArrayLength)
    }  
  }

Answer 1

很难理解你的函数如何相互影响，但这可能就是你想要的

waitForSuccess = async () => {
  let success = false
  let dbIndex
  do {
    dbIndex = this.getUniqueRandomNumber(this.state.ArrayLength)
    success = !(await this.hasDataBeenSeen(this.state.Data[dbIndex].Key))
  } while (!success)
  return dbIndex
}

// use it somewhere

const dbIndex = await this.waitForSuccess()
this.setState({ finalString: this.state.Data[dbIndex].Key })