javascript - 将按钮 onmouseover 更改为 onclick

Question

changeButton.className = 'change button types-popup';
const changePopup = document.createElement('div');
changeButton.appendChild(changePopup);
changeButton.onmouseover = e => {
   if (!e.target.classList.contains('types-popup')) return;
   changePopup.innerHTML = '':
   renderTypes(changePopup, type => {
       defectData.action = 'update';
       defectData.type = type.id;
       textDiv.children[0].innerText = type.description;
       closePopups();
   });

我完全不懂js。那么你可以帮我将这个 onmouseover 更改为 onclick 打开/关闭吗？谢谢!

Answer 1

只需将 changeButton.onmouseover 更改为 changeButton.onclick

参见onclick

changeButton.className = 'change button types-popup';
const changePopup = document.createElement('div');
changeButton.appendChild(changePopup);
changeButton.onclick = e => {
   if (!e.target.classList.contains('types-popup')) return;
   changePopup.innerHTML = '':
   renderTypes(changePopup, type => {
       defectData.action = 'update';
       defectData.type = type.id;
       textDiv.children[0].innerText = type.description;
       closePopups();
   });