javascript - 合并/替换数组中具有相同 ID 的对象

Question

我有2个数组，我尝试根据它们的id合并2个数组，并且数组的顺序必须与第一个数组相同

array1: [
{id: student1, name: 'Jacky', course: ''},
{id: student2, name: 'Taylor', course: ''},
{id: student3, name: 'David', course: ''},
{id: student4, name: 'Aisy', course: ''},
{id: student5, name: 'Micky', course: ''}
];

和

array2: [
{id: student1, name: 'Jacky', course: 'science'},
{id: student2, name: 'Taylor', course: 'biology'},
{id: student1, name: 'Jacky', course: 'math'},
{id: student4, name: 'Aisy', course: 'chemistry'},
{id: student1, name: 'Jacky', course: 'history'},
];

我希望结果是这样的

array:[
{id: student1, name: 'Jacky', course: 'science'},
{id: student1, name: 'Jacky', course: 'math'},
{id: student1, name: 'Jacky', course: 'history'},
{id: student2, name: 'Taylor', course: 'biology'},
{id: student3, name: 'David', course: ''},
{id: student4, name: 'Aisy', course: 'chemistry'},
{id: student5, name: 'Micky', course: ''}
];

Answer 1

你可以这样做:

    const result = [];
    array1.forEach(a1 => {
      result.push(a1);
      array2.forEach(a2 => {
        if (a1.id === a2.id) {
          result.push(a2);
        }
      });
    });

或仅一行代码:

const result =([...array1,...array2]).sort((a, b) => a.id - b.id);